course Phy 201 I don't believe I was able to answer all the questions. The program kept having script errors and then closing the query on me. It did this multiple times so I did until I got the script error and sent the work completed up to that point.
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20:53:35 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> Standard deviation of a set of numbers, is determined by taking a few select samples and figuring out their mean and then the deviation away from the mean from the samples. Then, taking those devations and squaring them and then finally the average(deviations added up and divided by one less of the number of samples) of those squared deviations after you take the square root of it is standard deviation. confidence assessment: 2
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20:56:04 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> Each person doing the experiment could justify that there line would best interpret the best line fit for the certain data points that were on the graph. Well it all depends on were they put there best fit line and then how they picked there data points. The slope and vertical intercept should be faily close though if give the same graph of points. confidence assessment: 2
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20:58:21 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> Velocity is a numerical value that represents how fast an object is moving and the direction that it is moving in. It is a rate, you're describing the change in position of an object to the the change in elapsed time or that duration. confidence assessment: 2
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20:59:29 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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RESPONSE --> I believe i was fairly close in my answer to velocity and why it is considered a rate. self critique assessment: 3
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21:01:56 Given average speed and time interval how do you find distance moved?
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RESPONSE --> Take the reciprocal of distance moved and add it to both sides of the equation and then solve for distance traveled. confidence assessment: 2
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21:04:42 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> That went over my head. I understand it now I over thought the question i believe. That was a simple question i made it too hard. self critique assessment: 1
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21:05:57 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> Divide the average speed by the distance to figure out the corresponding time interval. confidence assessment: 2
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21:07:33 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> That is not what I exactly said in my answer, but it is what i meant. I said Avererage speed by distance, but i mean distance/average speed in terms of 150/50=3h self critique assessment: 3
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21:09:27 Given time interval and distance moved how do you get average speed?
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RESPONSE --> Divide the distance traveled by time interval. confidence assessment: 2
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21:14:02 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> I believe I answered the question correctly..and understood the concept of the question. self critique assessment: 3"