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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
Slope1 vAve=1.25m/s
vf=2.5m/s
'dv=2.5/s
aAve=2.5m/s/8s=.3m/s^2
Slope2 vAve=2m/s
vf=4m/s
'dv=4m/s
aAve=.8m/s^2
The change in acceleration is a1 - a2= .5m/s^2. The change in the slope is .05. The rate of change is .5m/s^2 / .05units= 10m/s^2.
Very good. Note that the slope is close to the acceleration of gravity. If constant road slopes can be located and measured, this procedure can give very good results for the acceleration of gravity.
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25 min
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&#Your work looks good. See my notes. Let me know if you have any questions. &#