Math22open

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course Mth 151

1/16/2012 10:57PM

001. `Query 1

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Question: `qQuery 2.1.12 counting #'s 4 to 14

List the elements of the set.

 

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Your solution:

{4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14}

confidence rating #$&*: 3

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Given Solution:

`a**A list of the elements would just be 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14. **

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Self-critique (if necessary):

In my answer I put {} around my set but there are not curly brackets around the Given Solution. Was it wrong for me to put the curly brackets, all the answers for the example problems for “Listing Element of Sets” in the textbook have them?

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Self-critique Rating: 3

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Question: `qquery 2.1.24 listing for set of presidents between LBJ and Clinton

 

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Your solution:

{Richard M. Nixon, Gerald R. Ford, James Carter, Ronald Reagan, George H. Bush}

confidence rating #$&*: 3

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Given Solution:

`a** A listing would be {}{}{Lyndon Johnson, Richard Nixon, Gerald Ford, Jimmy Carter, Ronald Regan, George HW Bush, William Clinton}.{}{}Set-builder notation is {x|x is a president who served between Lyndon Johnson and William Clinton}

x is a variable and the condition 'x is a president who served between Lyndon Johnson and William Clinton' tells you what possible things the variable can be.

COMMON ERROR: It's incorrect to say {x | x is the set of presidents who served between Johnson and Clinton}.

x is a president, not a set of presidents. Should be {x|x is a president who served between Lyndon Johnson and William Clinton} **

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Self-critique (if necessary):

In my answer I didn’t list LBJ or Bill Clinton but it the Given Solution they are listed. Wouldn’t you leave the endpoints off since it is asking between LBJ and Clinton?

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Self-critique Rating: 3

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That would be correct.

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Question: `q2.1.40 finite or infinite: set of rat #'s 0 to 1

 

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Your solution:

The set would be infinite because we could never list all the rational numbers between 0 and 1 because it would include and infinite number of fractions.

confidence rating #$&*: 3

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Given Solution:

`a** Rational numbers have form p/q, where p and q are integers. Numbers like 5/8, 57/31, -3/5, -57843/7843, etc.

The subset {1/2, 1/3, 1/4, 1/5, ... } is just by itself an infinite set of rational numbers between 0 and 1.

Then you have things like 348/937, and 39827389871 / 4982743789, and a whole infinite bunch of others. There are thus infinitely many rational numbers in any interval of the real line.

COMMON MISCONCEPTION: finite, because it doesn't go on forever

Rational numbers have form p/q, where p and q are integers. Numbers like 5/8, 57/31, -3/5, -57843/7843, etc. Not all of these lie between 0 and 1, of course. **

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Self-critique (if necessary): OK

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Self-critique Rating: OK

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Question: `q2.1.48 n(A), A={x|x is a U.S. senator}

What is n(A) and why?

 

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Your solution:

n(A)equals 100

n(A) is the total number of senators and theirs 2 senators from each state and 50 states so there are 100 senators

confidence rating #$&*: 2

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Given Solution:

`a** n(A) stands for the number of elements in the set--in this case for the number of senators. There are 100, 2 from each State. So n(A) = 100. **

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Self-critique (if necessary): OK

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Self-critique Rating: OK

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Question: `qquery 2.1.54 {x|x is neagtive number}

 

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Your solution:

This set would be well defined since you can determine without a doubt that a number is belongs in the set or not. If a given number is negative it belongs in this set.

confidence rating #$&*: 3

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Given Solution:

`a** This notation means all possible values of x such that x is a negative number.

The question is whether the set is well-defined or not.

It is in fact well-defined because there is a definite way to decide whether a given object is an element of the set, because there is a definite way to determine whether an object is a negative number or not.

ALTERNATIVE ANSWER: The set is well-defined because you have a criterion by which you can definitely decide whether something is or is not in the set. **

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Self-critique (if necessary): OK

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Self-critique Rating: OK

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Question: `q2.1.74 (formerly 2.1.72) This was not assigned, but you should be able to answer based on your work on similar problems: It is or is it not true that 2 is not not subset of {7,6,5,4}?

 

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Your solution:

This statement is true because 2 it is not a part of the set.

confidence rating #$&*: 3

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Given Solution:

`a** The statement is that 2 is not a subset. The statement is true because 2 isn't even a set, it's just a number. {2} is a set and could be a subset of something. 2 is just a number; it isn't a set so it can't be a subset of anything.

The usual answer is that 2 isn't a subset because 2 isn't in the set. However that's not the correct reason. The correct reason is that 2 isn't a set and a subset must be a set.

COMMON MISCONCEPTION: the statement says that 2 is not a subset, not that it is not an element of the set. So the reason it's not a subset is that 2 isn't a set at all, so it can't be a subset of anything. **

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Self-critique (if necessary):

I said it was true because 2 was not part of the set, but it’s true because it’s not a set at all.

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Self-critique Rating: 3

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Question: `q2.1.86 (formerly 2.1.84). This was not assigned but you did answer several questions related to the sets C={4,10,12}, B={2,4,8,10}, and should be able to answer this.

Is it true or false that every element of C is also an element of B? Be sure to include your reasoning.

 

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Your solution:

It is false that every element of C is also an element in B because 12 is in C but not in B

confidence rating #$&*: 3

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Given Solution:

`a** Specifically it's false because the element 12 is in C but not in B. **"

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Self-critique (if necessary):

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Self-critique rating:

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Question: `q2.1.86 (formerly 2.1.84). This was not assigned but you did answer several questions related to the sets C={4,10,12}, B={2,4,8,10}, and should be able to answer this.

Is it true or false that every element of C is also an element of B? Be sure to include your reasoning.

 

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Your solution:

It is false that every element of C is also an element in B because 12 is in C but not in B

confidence rating #$&*: 3

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Given Solution:

`a** Specifically it's false because the element 12 is in C but not in B. **"

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Self-critique (if necessary):

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Self-critique rating:

#*&!

@&

Very good answers. See my one note.

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