qa 9

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course MTH 163

Hello! Things are looking a bit more 'up' than before. Finally have time to get some things accomplished and lay waste to the To Do list.Oct. 26th @ 2:15 PM

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If your solution to stated problem does not match the given solution, you should self-critique per instructions at

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm

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Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

009.

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Question: `q001. Note that this assignment has 2 questions

For the function y = 1.1 x + .8, what are the coordinates of the x = x1 point, in terms of the symbol x1? What are the coordinates of the x = x2 point, in terms of the symbol x2?

What therefore is the rise between these two points, and what is the run?

What is the average slope of the graph between these two points? Be sure to simplify your result.

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Your solution:

- I don’t understand this problem, for example how it would be used and where the x = x1 relation comes in, and obviously I couldn’t possibly finish the rest without the knowledge to complete the first.

-

confidence rating #$&*:

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Given Solution:

In terms of the symbol x1 the coordinates of the x = x1 point are ( x1, 1.1 x1 + .8) and the coordinates of the x = x2 point are ( x2, 1.1 x2 + .8).

The rise between the two points is therefore

rise = (1.1 x2 + .8) - (1.1 x1 + .8) = 1.1 x2 + .8 - 1.1 x1 - .8 = 1.1 x2 - 1.1 x1.

The run is

run = x2 - x1.

The slope is therefore (1.1 x2 - 1.1 x1) / (x2 - x1) = 1.1 (x2 - x1) / (x2 - x1) = 1.1.

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Self-critique (if necessary): After following the example I could see where this was going. Basically all I had to do was, for the symbol (which I deduced to be said as ‘x sub one’ and ‘x sub two’. I still don’t fully understand the way the first question was worded. As much, I’m having difficulty seeing where the x = x1 comes into play. But as the problem proceeded the clouds began to part, so to speak. But it’s still cloudy.

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Self-critique rating:

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Question: `q002. For the function y = 3.4 x + 7, what are the coordinates of the x = x1 point, in terms of the symbol x1? What are the coordinates of the x = x2 point, in terms of the symbol x2?

What therefore is the rise between these two points, and what is the run?

What is the average slope of the graph between these two points? Be sure to simplify your result.

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

- For the function y = 3.4 x + 7, what are the coordinates of the x = x1 point, in terms of the symbol x1?

o (x1, 3.4x1 + 7)

- Symbol x2?

o (x2, 3.4x2 + 7)

- Rise?

o (3.4x2 +7 - 3.4x1 - 7)

- Run?

o (3.4x2 - 3.4x1)

- Slope?

o 14

confidence rating #$&*:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

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Given Solution:

In terms of the symbol x1 the coordinates of the x = x1 point are ( x1, 3.4 x1 + 7) and the coordinates of the x = x2 point are ( x2, 3.4 x2 + 7).

The rise between the two points is therefore

rise = (3.4 x2 + 7) - (3.4 x1 + 7) = 3.4 x2 + 7 - 3.4 x1 - 7 = 3.4 x2 - 3.4 x1.

The run is

run = x2 - x1.

The slope is therefore (3.4 x2 - 3.4 x1) / (x2 - x1) = 3.4 (x2 - x1) / (x2 - x1) = 3.4.

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Self-critique (if necessary):

- Why did you remove the 7’s? Do you have something against the 7’s?

All humor aside, mathematically speaking; why are they cleared? As much, why isn’t the run 3.4x2 - 3.4x1?

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In the expression

(3.4x2 +7 - 3.4x1 - 7)

we add 7, then we later subtract 7. So the 7's have no net effect on the result. That is,

(3.4x2 +7 - 3.4x1 - 7) = (3.4x2 - 3.4x1 ).

And the run goes from x = x1 to x = x2. The difference is x2 - x1. The 3.4 has nothing to do with x values, a lot to do with the y values.

Humor, incidentally, is always appreciated as a way to help maintain sanity, if nothing else.

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#*&!

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I'm glad things are going better for you.

Check my notes and let me know if you have questions.

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