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phy 201
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_04.1_labelMessages **
The problem:
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
• Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
• Sketch a straight line segment between these points.
• What are the rise, run and slope of this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): Rise: 40cm/s-10cm/s=30cm/s
Run: 9s-4s=5s
Slope: 30cm/s/5s=6cm/s^2
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• What is the area of the graph beneath this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): The area beneath the graph is the total amount of distance traveled.
30cm/s/2=15cm/s+10cm/s=25cm/s
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30cm/s/2=15cm/s is a correct statement.
30cm/s/2=15cm/s+10cm/s is not a correct statement, nor is it true that
30cm/s/2=25cm/s.
Your statement
30cm/s/2=15cm/s+10cm/s=25cm/s
is not correct, though
15cm/s+10cm/s=25cm/s
is a correct statement.
For your own sake, and for that of any reader who might take the statement seriously without knowing how to interpret it, be careful to avoid incorrect mathematical statements.
That said, i know what you intended and your result is correct.
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25cm/s*5s=125cm.
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Good, but be sure to see my note about avoiding incorrect mathematical statements.
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