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phy 201
Your 'cq_1_08.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_08.1_labelMessages **
A ball is tossed upward with an initial velocity of 25 meters / second. Assume that the acceleration of gravity is 10 m/s^2 downward.
• What will be the velocity of the ball after one second?
answer/question/discussion: ->->->->->->->->->->->-> :
v0=+25m/s up
a=-10m/s^2 down
dt=1
vf=25+-10*1=
vf=15m/s
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• What will be its velocity at the end of two seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
vf=25+10*2
vf=5m/s
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• During the first two seconds, what therefore is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve=25+5/2
vAve=15m/s
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• How far does it therefore rise in the first two seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
15m/s*2s=30m
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• What will be its velocity at the end of a additional second, and at the end of one more additional second?
answer/question/discussion: ->->->->->->->->->->->-> :
vf=25+10*3
vf=-5
vf=25+10*4
vf=-15
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• At what instant does the ball reach its maximum height, and how high has it risen by that instant?
answer/question/discussion: ->->->->->->->->->->->-> :
The ball will reach it’s max height when the velocity reaches 0.
By observation I note that 2.5 seconds will have a vf=0.
vf=25+10*2.5
vf=0m/s
dt=2.5s
vAve=25/2
vAve12.5m/s
12.5*2.5=31.25m
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• What is its average velocity for the first four seconds, and how high is it at the end of the fourth second?
answer/question/discussion: ->->->->->->->->->->->-> :
vf=-15
vAve=25-15/2=5m/s
5m/s*4s=20m
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• How high will it be at the end of the sixth second?
answer/question/discussion: ->->->->->->->->->->->-> :
vf=25-10*6=-35m/s
vAve=25-35=-10m/s
ds=-10*6=-60m.
The all would be at -60 meters if the ground had not stopped it before then.
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http://vhcc2.vhcc.edu/dsmith/forms/common_questions/ph1_cq_I_08_1.htm
&#Very good responses. Let me know if you have questions. &#