course Mth 271
This is the q&a assignment #2, Im still not sure if this is how I am suppost to submit it.
This is very nearly the correct means of submitting the assignment. However this is not a copy of the SEND file created by running the program. I'm not sure how you created this file, but obviously it was created by the program; however it is not a copy of the SEND file.
It's less work for you and provides me with more complete and more readable information if you submit an actual, unedited copy of the SEND file.
One note: Never include your name or access code except in response to the boxes that request it.
Your work has been received. Please scroll to the end of the document to see any inserted notes (in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.
Q&A Assignment
`q001. Recall the stock value problem, where March, July and December values were $5000, $5300 and $5500.
Construct a graph of stock value vs. number of month (e.g., 1 for Jan, 2 for Feb, etc.). You will have three points on your graph, one corresponding to the March value, one to the July value, and one to the December value. Stock value will be on the y axis and month number on the x axis. Your first point, for example, will be (3, 5000), corresponding to $5000 in March.
Connect your three points with straight lines--i.e., connect the first point to the second and the second to the third.
What is the slope of your line between the first and second point, and what is the slope of your line between the second in the third point? Recall that slope is rise / run.
Response:
The slope of the line between the first and second points is 75. (slope=rise/run; (5300-5000/7-3; 300/4; 75)).
The slope of the line between the second and third point is 40. (5500-5300/12-7; 200/5; 40)
The three points were (3, 5000), (7, 5300), (12, 5500)
Answer:
The three points on the graph are (3, 5000), (7, 5300) and (12, 5500).
The rise between the first point and the second is from 5000 to 5300, or 300, and the run is from 3 to 7, or 4, so the slope is 300 / 4 = 75. Note that the 300 represents $300 and the 4 represents 4 months, so the slope represents $300 / (4 months) = $75 / month, which is the average rate of change during the first time interval.
The rise between the second point and the third is from 5300 to 5500, or 200, and the run from 7 to 12 is 5, so the slope is 200 / 5 = 40. This slope represents the $40/month average rate of change during the second time interval. Click on 'Next Picture' to see the graph.
`q002. Look at your results for the slopes, and look the results for the average rates of change. What do you notice? In what way then does the graph represent the average rate of change?
Response:
The slop of the lines is equilavent to the average rates of change in this problem. The graph represents the average rates of change by giving the slope which for the first two points means $75 per month, and for the second two points $40 per month.
Answer:
We see from this example that the slope of a graph of value vs. clock time represents the rate at which value is changing with respect to clock time.
`q003. To what extent do you think your graph, consisting of 3 points with straight line segments between them, accurately depicts the detailed behavior of the stocks over the 9-month period?
Response:
If the stocks changed values at $75 each month for the first 4 months and at $40 per month for the last 5 months then the graph was fairly accurate.
However, they could have changed at different rates each month that just averaged to $75 per month; for example it could have changed $150 one month and $0 the next during the first four months. If this was the case then the graph would not accurately depict the behavior of the stocks over the 9 month period.
Answer:
Stocks can do just about anything from day to day-they can go up or down more in a single day than their net change in a month or even a year. So based on the values several months apart we can't say anything about what happens from day to day or even from month to month. We can only say that on the average, from one time to another, the stocks changed at a certain rate.
`q004. From the given information, do you think you can accurately infer the detailed behavior of the stock values over the nine-month period?
Response:
No not accurately because you dont know that they grew at a uniform rate. You can only assume based on the average.
Answer:
Not on a day-to-day basis, and not even on a month-to-month basis. All we can see from the given information is what might be an average trend.
"
Your responses are good and it appears you understand these situations very well.
However do see my note at the beginning about sending the SEND files.