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phy 201
Your 'cq_1_03.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball starts with velocity 0 and accelerates uniformly down a ramp of length 30 cm, covering the distance in 5 seconds.
• What is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Average velocity = Length or distance of travel divided by the Time
= 30cm / 5sec = 6cm/sec.
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• If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
You know its average velocity, and you know the initial velocity is zero.
What therefore must be the final velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Its final velocity would be double its average velocity: 6cm/sec * 2 = 12cm/sec
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• By how much did its velocity therefore change?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
6cm/sec / 2.5sec = 2.4cm/sec/sec
Or would you take the change in velocity and divide it by same clock time instead of dividing it by the half of the original clock time:
6cm/sec / 5sec = 1.2cm/sec/sec?????????????????????????????????
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• At what average rate did its velocity change with respect to clock time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Again I am unsure as to how to answer this question. What do I look for that would give be the information I need to answer this question? Does the answer lie within the final answer of the average rate of change of velocity formula???????????????????????????????????
You were on the right track in your calculations. See the discussion at the link, which will answer your questions.
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• What would a graph of its velocity vs. clock time look like? Give the best description you can.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The line would start at the lower left hand side of the graph and as time increase the velocity would increase and the line would go up and to the right, with a straight and constant slope.
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Check the links and submit a revision. You'll understand quickly and shouldn't require long to revise accordingly.
&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#