#$&*
course Phy 231
2-12-11 about 9:45am
Determine the acceleration of an object whose velocity is initially 15 cm/s and which accelerates uniformly through a distance of 51 cm in 4.1 seconds.
(51cm/4.1s)(2) - 15cm/s= vf
@& vf is double vAve only if v0 = 0.
You already have values three of the five quantities v0, vf, `dt, a, `ds. v0 is among those you don't have values for, so its value is determined by the three values you do have.
You cannot, therefore, assume v0 to be zero.*@
9.88cm/s=vf
dv= (9.88cm/s - 15cm/s)= -5.12cm/s
aAve= (-5.12cm/s)/(4.1s)= -1.25cm/s^2
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@& You made an invalid assumption, and your results contradict the given information.
See also my note.
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