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Phy 231
Your 'cq_1_08.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball is tossed upward with an initial velocity of 25 meters / second. Assume that the acceleration of gravity is 10 m/s^2 downward.
• What will be the velocity of the ball after one second?
answer/question/discussion: ->->->->->->->->->->->-> :
-10m/s^2 *1s= -10m/s
25m/s - 10m/s= 15m/s= velocity of the ball after 1sec.
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• What will be its velocity at the end of two seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
25m/s - 20m/s= 5m/s
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• During the first two seconds, what therefore is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> :
(25m/s + 5m/s)/2= 15m/s
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• How far does it therefore rise in the first two seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
2s * 15m/s= 30m
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• What will be its velocity at the end of a additional second, and at the end of one more additional second?
answer/question/discussion: ->->->->->->->->->->->-> :
25m/s - 30m/s= -5m/s @3s
25m/s - 40m/s= -15m/s @4s
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• At what instant does the ball reach its maximum height, and how high has it risen by that instant?
answer/question/discussion: ->->->->->->->->->->->-> :
-10m/s * 2.5s= -25m/s
25m/s - 25m/s= 0m/s @2.5s= instant its at max height
25m/s/2= 12.5m/s= vAve over 2.5s
ds= 12.5m/s * 2.5s= 31.25m= max height
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• What is its average velocity for the first four seconds, and how high is it at the end of the fourth second?
answer/question/discussion: ->->->->->->->->->->->-> :
(25m/s - 15m/s)/2= 5m/s = vAve @4s
ds= 5m/s * 4s= 20m= height @4s
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• How high will it be at the end of the sixth second?
answer/question/discussion: ->->->->->->->->->->->-> :
25m/s - 60m/s= -35m/s @6s
(25m/s -35m/s)/2= -5m/s= vAve @6s
ds= -5m/s * 6s= -30m @6s
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Very good responses. Let me know if you have questions.