#$&*
Phy 231
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
• How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium? #$&*
answer/question/discussion: ->->->->->->->->->->->-> :
• What reasonable assumption did you make to arrive at your answers? #$&*
answer/question/discussion: ->->->->->->->->->->->-> :
1sec to get from one extreme to the other, ½ sec to get from extreme point to equilibrium, and 1 ½ sec to go from extreme point to equilibrium to opposite extreme point and back to equilibrium.
The assumption made is that the time for ½ a cycle is half the 2 sec, and that the times are evenly spaced out in time amongst one another.
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@& Essentially you have assumed that the time required for any half-cycle is the same as the time required for any other, which is consistent with the steady rhythm of the pendulum.
Very good.*@