week5quiz2

#$&*

course Phy 231

2-19-11 about 4:00pm

If the slope of a graph of the acceleration of a cart vs. the number of paper clips attached by a string and suspended over a pulley is ( 25 cm/s2) / clip, and if the slope of a graph of number of paper clips needed to maintain equilibrium vs. ramp slope is 39 clips / unit of ramp slope, then how many cm/s2 of acceleration should correspond to 1 unit of ramp slope? If 43 clips are necessary to match the mass of the cart, then if we could apply this force to the cart without the extra mass of all those clips, what would be the acceleration of the cart?39/25= 1.56 this is the ratio

43-39clips= 4clips * 1.56= 6.24

25cm/s^2/6.24= 4cm/s^2

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@& At 25 cm/s^2 per clip, and 39 clips per unit of slope, you would expect the acceleration to be

25 cm/s^2 / clips * 39 clips / unit of slope = 975 cm/s^2 / unit of slope.

The force exerted by 43 clips, applied to the cart, would apparently accelerate it at 43 * 25 cm/s^2 = 1075 cm/s^2.*@