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Phy 231
Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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If the slope of a graph of number of paper clips needed to maintain equilibrium vs. ramp slope is 38 clips / unit of ramp slope , and if the slope of a graph of the acceleration of a cart vs. the number of paper clips attached by a string and suspended over a pulley is ( 26 cm/s2) / clip, then how many cm/s2 of acceleration should correspond to 1 unit of ramp slope? If we require 39 clips to match the mass of the cart, then if we could apply this force to the cart without the extra mass of all those clips, what would be the acceleration of the cart?
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My question is about 1 of the problems on test #1, I was looking at it to prepare for test #1 and I'm not sure how to get started. This type of problem seems familiar, but I can't remember/find it in any of the work I've done. Would you tell me where I can find either an example of this or similar example? Any other info would be appreciated too, thanks
@& If you need 38 clips / unit of ramp slope, and the slope of the graph is 26 cm/s^2 / clip, then the acceleration corresponding to ramp slope 1 is 38 clips / unit of slope * 26 cm/s^2 / clip = 1000 cm/s^2 / unit of slope (approx.).
The acceleration corresponding to 39 clips would be 39 clips * 26 cm/s^2 / clip = 1000 cm/s^2 (approx..).
I believe one result is a little under, the other a little over, 1000 cm/s^2. In any case the two results differ by 26 cm/s^2.*@
*** File was originally submitted on 3/21 or 3/22, was critiqued by failed to post. ***