question form

Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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First be sure you understand why the x axis is the set of points in the coordinate plane where y = 0, and the y axis the set of points where x = 0. If this isn't completely clear to you, sketch a set of coordinate axes and label several points on the x axis with their coordinates, and do the same for several points on the y axis.

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The x intercept of a graph is a point where y = 0, and a y intercept is a point where x = 0.

So to find the x intercepts corresponding to an equation, you set y equal to zero and solve the resulting equation for x.

And to find the y intercepts corresponding to an equation, you set x equal to zero and solve the resulting equation for y.

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In the case of the equation you give, let's find the y intercepts.

This requires that we set x = 0, then solve for y.

Setting x = 0 the equation

I'm confused on finding the incepts of a circle. For example:

(x+3)^2+(y-2)^2=16

becomes

(0+3)^2 + (y-2)^2 = 16

so that

9 + (y-2)^2 = 16

and

(y - 2)^2 = 7.

Thus

(y - 2) = +- sqrt(7)

giving us the equations

y-2 = sqrt(7), with solution y = 2 + sqrt(7)

and

y+2 = sqrt(7), with solution = -2 + sqrt(7).

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The y intercepts therefore occur at

(0, 2 + sqrt(7))

and

(0, -2 + sqrt(7)).

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The x intercepts are easily found by an analogous substitution and solution.

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