course PHY 201 I am not sure if all the questions were completed when I got to this question my computer said there was a runtime error so I went through it again and it did the same thing assignment #001001.
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20:30:40 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> First you take a random sample of the data then find the mean of those. Then subtract each of the data points from the mean then square them then average them dividing by the total number -1 if under 30 samples then take the square root of that answer confidence assessment: 3
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20:33:05 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> Fitting a line to data point - find the line that rarely passes thru any given point but is close to all points. This is difficult in many situations because 2 people could decide the best fit line is in 2 different places confidence assessment: 3
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20:34:36 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> Velocity is the rate at which the position of an object changes confidence assessment: 3
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20:36:03 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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RESPONSE --> A rate is a change divided by a change so velocity is the change in distance divided by the change in time self critique assessment: 3
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20:38:29 Given average speed and time interval how do you find distance moved?
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RESPONSE --> multiply average speed by the time confidence assessment: 3
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20:38:39 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> self critique assessment: 3
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20:39:18 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> Divide distance moved by average speed to get time confidence assessment: 3
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20:39:33 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> self critique assessment: 3
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20:40:15 Given time interval and distance moved how do you get average speed?
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RESPONSE --> V=distance/time confidence assessment: 3
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20:40:23 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> self critique assessment: 3"