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phy121
Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_19.2_labelMessages **
Sketch a vector representing a 10 Newton force which acts vertically downward.
• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion: ->->->->->->->->->->->-> :
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• What are the x and y components of the equilibrant of the force?
answer/question/discussion: ->->->->->->->->->->->-> :
x component = 10 newtons * cos 250= -3.4 newtons
y component = 10 newtons * sin 250 = -9.4 newtons
the equilibrant force is then 3.4 newtons for the x componenet and 9.4 newtons for the y component
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&#Your work looks very good. Let me know if you have any questions. &#