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phy121
Your 'cq_1_19.3' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An object moving in the direction 120 degrees (as measured counterclockwise to the positive x axis) encounters a net force whose direction is 270 degrees.
• Sketch the force and its component along the line of motion, as well as its component perpendicular to the line of motion.
answer/question/discussion: ->->->->->->->->->->->-> :
I constructed the sketch which shows the direction vector at 120 degrees from the origin into the 2nd quadrant. The force vector is the negative y axis.
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• Suppose you are facing in the direction of motion. Do you perceive the component of the force along the line of motion to be forward or backward? It this component in the direction of motion or opposite to the direction of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
if you are facing the direction of motion which is the 120 degree angle you would have to turn (270-120)150 degrees to be facing in the direction of force.
if you are facing the direction opposite of motion, you would have to turn 30 degrees to face the direction of the force.
Therefore if you are facing forward you would perceive the force to be opposite to the direction of motion.
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• Will the object speed up, slow down or maintain a constant speed?
answer/question/discussion: ->->->->->->->->->->->-> :
since the force is closer to the backward direction the object will slow down because a net force component in the opposite direction of motion will cause a slow down.
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• If you are facing in the direction of motion, then the line perpendicular to the direction of motion will run to your right and to your left. Is the component of the force perpendicular to the line of motion directed to the right or to the left?
answer/question/discussion: ->->->->->->->->->->->-> :
the direction of motion is at 120 degrees then in order to get to the 270 degrees you would turn to your left 150 degrees or to your right 210 degrees. So the component is directed to the left.
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• Will the object veer to the right, to the left or maintain straight-line motion?
answer/question/discussion: ->->->->->->->->->->->-> :
The force vector will veer to the left
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• Which is greater in magnitude, the component of the force along the line of motion or the component perpendicular to the line of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
the 2 vectors are at 270 degrees and 120 degrees. 270 -120 = 150 degrees. I would think the component in the parallel direction is greater because the force vector is only 30 degrees from the direction parallel to motion.
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&#Your work looks very good. Let me know if you have any questions. &#