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phy121
Your 'cq_1_27.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball of mass 400 grams is immersed in water. The ball is suspended in the water by a rubber band chain which exerts a tension force of 2.5 Newtons on the ball.
• What is the weight of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
the weight of the ball would be the force exerted by gravity
weight = .4 kg * 9.8 m/sec^2 = 3.92 newtons
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• What is the buoyant force on the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
the net force I zero since 3.92 N acts downward and 2.5 n tension acts upward
the buoyant force must be 3.92N - 2.5 N = 1.42 Newtons
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• What therefore must be its volume?
answer/question/discussion: ->->->->->->->->->->->-> :
the buoyant force on an object is equal to the weight of the water it displaces and water has a weight density of 1000kg/m^3. The ball must displace an amount of water which weight 1.42 newtons. So the mass density of the water is 9.8 m/ec^2 * 1000 kg/m^3 = 9800 Newtons/m^3
the weight of the water displaced is then
v*9800N/m^3=1.42 newtons and V = .000145 m^3
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• What is its density?
answer/question/discussion: ->->->->->->->->->->->-> :
density = mass/volume = 400 grams / 145 cm^3 = 2.8 grams/cm^3
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&#Very good responses. Let me know if you have questions. &#