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phy 121
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_05.1_labelMessages **
The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
we are given that the average acceleration is 8 cm/sec^2
`dt = 3 seconds
v0 = 12 cm/sec
aAve = `dv/`dt
8 cm/sec^2 = ‘dv / 3 seconds
`dv = 24 cm/sec
Now we know that velocity is changing at the rate of 24m/sec
Beginning at 12 cm/sec velocity over the 3 second interval, the velocity after 3 seconds would be 12 cm/sec + 12 cm/sec + 12 cm/sec = 36 cm/sec
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• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve = (vf +v0)/2
= 36 cm/sec + 12 cm/sec = 48 cm/sec/2 = 24 cm/sec
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• How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
‘ds = vAVe * dt
= 24cm/sec * 3 sec = 72 cm
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&#Very good responses. Let me know if you have questions. &#