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phy121
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.1_labelMessages **
A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
`ds = v0dt + .5*a*dt^2
2m = 0*.64 seconds + .5*a*(.64sec)^2
2m = .2048sec^2 * a
a = 9.77 m/sec^2
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• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
ds = v0dt+.5adt^2
5m = 0*1.05sec + .5*a*(1.05sec)^2
5m = .55sec^2 * a
a =9.09 m/sec
relatively close to the 9.8 m/sec^2 which is the accepted value of acceleration of gravity
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• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
both are results are relatively close to 9.8 m/sec^2
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10 minutes
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4:10 pm 12/10/13
&#Very good responses. Let me know if you have questions. &#