cq_1_091

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phy 121

Your 'cq_1_09.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_09.1_labelMessages **

A ball accelerates uniformly as it rolls 20 cm down a ramp, starting from rest, in 2 seconds.

• What are its average velocity, final velocity and acceleration?

answer/question/discussion: ->->->->->->->->->->->-> :

v0 = 0, `ds = 20 cm, `dt = 2 seconds

v = `ds/`dt = 20/2 = 10 cm/sec

vAve = (vf+v0)/2

10cm/sec = (vf + 0)/2

vf = 20 cm/sec

a = `dv /`dt

= 20/2 = 10 cm/sec^2

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• If the time interval is in error so that it is 3% longer than the actual time interval, then what are the actual values of the final velocity and acceleration?

answer/question/discussion: ->->->->->->->->->->->-> :

then `dt = .03*2 = .06 +2 = 2.06 seconds for `dt

`ds =20cm and v0 =0

V = `dt/`dt = 20/2.06 = 9.71 cm/sec

Vf = 9.71*2 = 19.42 cm/sec and `dv = 19.42 cm/sec

A = `dv/dt = 19.42/2.06 = 9.43 cm/sec^2

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• What is the percent error in each?

answer/question/discussion: ->->->->->->->->->->->-> :

the original acceleration is 10cm/sec^2 and the actual acceleration is 9.43cm/sec^2

this is a difference of .57 cm/sec^2 / 10cm/sec^2 gives that the perecnetage is .06 or 6 percent of the original acceleration.

The original velocity is 10cm/sec and the correct is 9.71 cm/sec a difference of .29cm/sec/10 =.03 or 3 % of the original velocity

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• If the percent error is the same for both velocity and acceleration, explain why this must be so.

answer/question/discussion: ->->->->->->->->->->->-> :

no the percent for acceleration is 6% where the percent for velocity is 3% the reason is that when you find velocity you divide ds/`dt where the 3% error in time is calculated in. When you find acceleration you have `dv/`dt so you have the change in velocity which includes the first 3% error in time and divide it by the `dt which will include the 3% error in time again, doubling the percent error.

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• If the percent errors are different explain why it must be so.

answer/question/discussion: ->->->->->->->->->->->-> :

explained above

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15 minutes

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&#Very good responses. Let me know if you have questions. &#