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phy121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_11.1_labelMessages **
Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
f = m*a
= 12kg * 3m/sec^2 = 36 newtons
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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
f= m*a
20 newtons = 4kg * a
A = 5 m/sec^2
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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
m = fNet/a
10kg = 20netwons /a
A = 2 m/sec^2
I would know that there are other forces acting on the object besides my own because otherwise the acceleration would be 2m/sec^2 instead of 1.5 m/sec^2
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• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
I am pushing at a force of 20 newtons and the acceleration is found to be 1.5 m/sec^2
We found above that there is a frictional force of -.5 m/sec^2
F = m*a
= 10 kg * -.5 = -5 newtons
So Fnet would be 20 newtons -5 newtons = 15 newtons
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&#Your work looks very good. Let me know if you have any questions. &#