course Phy 201 I don't think that this assignment is completed, but each time I tried to run it, I received an error message at the same place. n{P?q???|??W??s??assignment #001
......!!!!!!!!...................................
15:50:54 Explain in your own words how the standard deviation of a set of numbers is calculuated.
......!!!!!!!!...................................
RESPONSE --> Square each of the deviations. Average the squares of the deviations. Find the square root of the average of the squared deviations. If there are less than 30 deviations, find the average by dividing by 1 less than the number of deviations. confidence assessment: 2
.................................................
......!!!!!!!!...................................
15:56:44 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
......!!!!!!!!...................................
RESPONSE --> To fit a line, you must first find the slope using the slope formula of m=(y2-y1) / (x2-x1). Next, plug the slope into the linear equation of y = mx + b, and substitute points on the line for y and x. Then solve for b (the y intercept). Using these numbers from the equation, you can draw a best fit line. confidence assessment:
.................................................
......!!!!!!!!...................................
15:57:38 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
......!!!!!!!!...................................
RESPONSE --> To fit a line, you must first find the slope using the slope formula of m=(y2-y1) / (x2-x1). Next, plug the slope into the linear equation of y = mx + b, and substitute points on the line for y and x. Then solve for b (the y intercept). Using these numbers from the equation, you can draw a best fit line. confidence assessment: 2
.................................................
€???????????? assignment #001 001. Physics I 01-27-2007
......!!!!!!!!...................................
15:59:07 Explain in your own words how the standard deviation of a set of numbers is calculuated.
......!!!!!!!!...................................
RESPONSE --> Square each of the deviations. Average the squares of the deviations. Find the square root of the average of the squared deviations. If there are less than 30 deviations, find the average by dividing by 1 less than the number of deviations. confidence assessment: 3
.................................................
......!!!!!!!!...................................
16:04:34 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
......!!!!!!!!...................................
RESPONSE --> To fit a line, you must first estimate the best fit. Next find the slope using the slope formula of m=(y2-y1) / (x2-x1). Next, plug the slope into the linear equation of y = mx + b, and substitute points on the line for y and x. Then solve for b (the y intercept). Uncertanties are likely because this process involves making some estimations which different people could estimate differently, resulting in different slope and verticle intercept points. confidence assessment: 2
.................................................
......!!!!!!!!...................................
16:23:38 Briefly state what you think velocity is and how you think it is an example of a rate.
......!!!!!!!!...................................
RESPONSE --> Velocity reveals the speed/ given amount of time in a certain direction. This is a rate because it compares the values of time and distance. confidence assessment: 2
.................................................
......!!!!!!!!...................................
16:25:43 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
......!!!!!!!!...................................
RESPONSE --> Change in position is better wording than I gave. self critique assessment: 2
.................................................
......!!!!!!!!...................................
17:29:35 Given average speed and time interval how do you find distance moved?
......!!!!!!!!...................................
RESPONSE --> 'ds = v * 'dt confidence assessment: 3
.................................................
......!!!!!!!!...................................
17:29:44 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
......!!!!!!!!...................................
RESPONSE --> OK self critique assessment: 3
.................................................
......!!!!!!!!...................................
17:42:21 Given average speed and distance moved how do you find the corresponding time interval?
......!!!!!!!!...................................
RESPONSE --> 'dt ='ds/ v confidence assessment: 1
.................................................
......!!!!!!!!...................................
17:44:03 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
......!!!!!!!!...................................
RESPONSE --> ok self critique assessment: 3
.................................................
......!!!!!!!!...................................
17:47:35 Given time interval and distance moved how do you get average speed?
......!!!!!!!!...................................
RESPONSE --> 'd dist = vAVE * 'dt 'd dist / 'd time = vAVE confidence assessment: 2
.................................................
......!!!!!!!!...................................
17:48:20 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
......!!!!!!!!...................................
RESPONSE --> OK self critique assessment: 3
.................................................
????????????O? assignment #001 001. Physics I 01-27-2007
......!!!!!!!!...................................
17:49:44 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
......!!!!!!!!...................................
RESPONSE --> self critique assessment:
.................................................
......!!!!!!!!...................................
17:49:54 Given average speed and time interval how do you find distance moved?
......!!!!!!!!...................................
RESPONSE --> confidence assessment:
.................................................
......!!!!!!!!...................................
17:49:58 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
......!!!!!!!!...................................
RESPONSE --> self critique assessment:
.................................................
......!!!!!!!!...................................
17:50:03 Given average speed and distance moved how do you find the corresponding time interval?
......!!!!!!!!...................................
RESPONSE --> confidence assessment:
.................................................
......!!!!!!!!...................................
17:50:06 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
......!!!!!!!!...................................
RESPONSE --> self critique assessment:
.................................................
......!!!!!!!!...................................
17:50:14 Given time interval and distance moved how do you get average speed?
......!!!!!!!!...................................
RESPONSE --> confidence assessment:
.................................................
......!!!!!!!!...................................
17:50:17 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
......!!!!!!!!...................................
RESPONSE --> self critique assessment:
.................................................
"