course

Here are some questions I have pertaining to various

assigments.

Randomized problems Asst 2 Problem 1:

An object which accelerates uniformly from rest will attain

a final velocity which is double its average velocity.

• What therefore is the final velocity of this ball?

• What average rate is the velocity of the ball therefore

changing?

Final Velocity = 2(12cm/s) = 24cm/s

`dvAve = `dv/ `dt = (12cm/ s) / 8.2s = 1.5 cm/s/s

**This is average velocity / change in clock time. The

average rate of change of velocity with respect to clock

time is (change in velocity) / (change in clock time). Can

you modify this solution and resubmit just this part? Be

sure to include your original work and this comment.

&&I do not understand why my answer was not the change in

velocity. Wouldn’t the change in velocity be: 24cm/s -

12cm/s = 12cm/s?

The change in velocity is the change from the beginning of the time interval to the end.

The average velocity generally occurs at neither the beginning nor the end of the time interval.

What is the velocity at the beginning of the time interval? What is the velocity at the end? What therefore is the change in velocity?

Then what is the average rate of change of velocity with respect to clock time?

An automobile accelerates uniformly down a constant incline,

starting from rest. It requires 10 seconds to cover a

distance of 132 meters. At what average rate is the velocity

of the automobile therefore changing?

`dvAve = `dv/ `dt = (13.2 m/s) / 10s = 1.32m/s/s

**Average rate of change of velocity is (change in

velocity) / (change in clock time). Your final result does

not follow from this definition. What is the change in

velocity? What is the change in clock time? What therefore

is the average rate of change of velocity with respect to

clock time? Please answer these questions and resubmit. Be

sure to include your original work and this comment.

&& I’m not sure what I did wrong in this problem either.

Here was my logic:

Average velocity: 132m / 10s = 13.2 m/s

Final velocity: 2(13.2 m/s) = 26.4 m/s

Change in velocity: 26.4 m/s – 13.2 m/s = 13.2m/s

Change in clock time: 10 sec

Acceleration: (13.2m/s) / (10s) = 1.32 m/s/s

Everything in your reasoning is good, except your use of average velocity to find change in velocity. Average velocity is not directly related to change in velocity. Change in velocity is determined by initial and final velocities.

Query Asst 1:

I receive an error message each time I attempt to complete

this assignement. This is why I have not answered the last

questions. What should I do?

What was the filename of the program you ran, where did you get it, did you run it online or from your desktop and if the latter when did you download it?

Giancoli 6th Edition Ch 1, Problems 1-15.

#11. I have no idea how to go about this problem. Will you

please offer suggestions?

I can’t answer questions by problem number and chapter. I need all the information in one place, within your message. You need to include an abbreviated statement of the problem, and a summary of what you do and do not understand. Then I can give you a reply which is very specific to what you need to know.

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