course Phy 202
I completed these assignments the first semester, so I just copied and pasted the original information.
That is acceptable. You've definitely paid your dues.
Your General CommentDescribe what you see on your first 10 clicks
Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.
I see 2 columns of numbers.
Your TIMER data from 20 fast clicks
1 114.8438 114.8438
2 115.0156 .171875
3 115.1563 .140625
4 115.3125 .15625
5 115.4688 .15625
6 115.625 .15625
7 115.8125 .1875
8 115.9688 .15625
9 116.1406 .171875
10 116.3281 .1875
11 116.5 .171875
12 116.6719 .171875
13 116.8438 .171875
14 117.0156 .171875
15 117.1875 .171875
16 117.3438 .15625
17 117.5156 .171875
18 117.7031 .1875
19 117.875 .171875
20 118.0625 .1875
21 118.2344 .171875
22 118.4063 .171875
Your average time interval for 20 time intervals
.1695
I added up the numbers by doing the following math:
.140625 + (.15625 * 5)+ (.171875 * 10) + (.1875 * 4) = 3.390625
Then I divided by the number of times given:
3.390625 / 20 = .1695
Your frequency distribution for the 20 time intervals (interval, number of times it was observed)
.140625, 1
.15625, 5
.171875, 10
.1875, 4
Your general comment to this point
Why did you observe only certain time intervals?
It must round off numbers that are so small they can't be recorded accuratly. It will still give a good estimate.
What did you see when you looked at the differences between time successive time intervals?
The numbers are very similar and all end with either a 3 or a 5. It appears that the timer program estimates to the nearest quarter.
Your time intervals for 7 complete breaths:
3.8125
5.71875
5.34375
5.140625
6.015625
5.84375
5.71875
5.328125
5.09375
Your general comment to this point:
Why did you rarely, if ever, observe that same time interval twice?
The former measurement was of a shorter time when the numbers needed to be more precise to see the difference. Over a longer period of time, as in the second calculation, the numbers are less likely to have such a small difference.
Do you think this program is accurate to .1 or .01 ...
The TIMER program is capable of determining the time between two events accurately to within about .001 second.
This was a guess. I really have no idea how to figure out this answer.
Copy of a few lines of your spreadsheet from the TIMER program.
It didn't work and the timer box dissappeared so I couldn't try again.
30 min
Your responses have been reviewed and everything looks good.
Please let me know if you have any questions related to this orientation assignment.
timer program
Your 'timer program' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
Your General Comment
Describe what you see on your first 10 clicks
I see 2 columns of numbers. I assume this is a
Your TIMER data from 20 fast clicks
1 114.8438 114.8438
2 115.0156 .171875
3 115.1563 .140625
4 115.3125 .15625
5 115.4688 .15625
6 115.625 .15625
7 115.8125 .1875
8 115.9688 .15625
9 116.1406 .171875
10 116.3281 .1875
11 116.5 .171875
12 116.6719 .171875
13 116.8438 .171875
14 117.0156 .171875
15 117.1875 .171875
16 117.3438 .15625
17 117.5156 .171875
18 117.7031 .1875
19 117.875 .171875
20 118.0625 .1875
21 118.2344 .171875
22 118.4063 .171875
Your average time interval for 20 time intervals
.1695
I added up the numbers by doing the following math:
.140625 + (.15625 * 5)+ (.171875 * 10) + (.1875 * 4) = 3.390625
Then I divided by the number of times given:
3.390625 / 20 = .1695
Your frequency distribution for the 20 time intervals (interval, number of times it was observed)
.140625, 1
.15625, 5
.171875, 10
.1875, 4
Your general comment to this point
Why did you observe only certain time intervals?
It must round off numbers that are so small they can't be recorded accuratly. It will still give a good estimate.
What did you see when you looked at the differences between time successive time intervals?
The numbers are very similar and all end with either a 3 or a 5. It appears that the timer program estimates to the nearest quarter.
Your time intervals for 7 complete breaths:
3.8125
5.71875
5.34375
5.140625
6.015625
5.84375
5.71875
5.328125
5.09375
Your general comment to this point:
Why did you rarely, if ever, observe that same time interval twice?
The former measurement was of a shorter time when the numbers needed to be more precise to see the difference. Over a longer period of time, as in the second calculation, the numbers are less likely to have such a small difference.
Do you think this program is accurate to .1 or .01 ...
The TIMER program is capable of determining the time between two events accurately to within about .001 second.
This was a guess. I really have no idea how to figure out this answer.
Copy of a few lines of your spreadsheet from the TIMER program.
It didn't work and the timer box dissappeared so I couldn't try again.
30 min"