course Phy 121 What are the average acceleration and final velocity of an object which accelerates uniformly from rest, attaining a velocity of 40 cm/sec in 13.6 seconds? How far does the object travel during the 13.6 seconds?First of all let's write what we know and what we are trying to find: Vo = 0 vAve = 40 cm / sec time = 13.6 sec Vf = ? average acceleration = ? vAve = (Vf + Vo) / 2 Plug in what we know: 40 cm / sec = (Vf + 0) / 2 Multiply both sides by 2 to get it to cancel on the right side of the equation. This leaves: 80 cm / sec = Vf + 0 Vf = 80 Now, how far does the object move? vAve = 'ds / 'dt 40 cm / sec = 'ds / 13.6 sec Multiply both sides by 13.6 to get it to cancel on the right side of the equation. This leaves: 'ds = 544 cm Acceleration: Average acceleration = 'dV / 'dt OR = (V2-V1)/(t2-t1) Average acceleration = 80 cm/sec / 13.6 sec = 5.88 cm/sec/sec"