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phy 201
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** CQ_1_24.2_labelMessages **
Seed 24 q2
A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
• Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
60*40cm/s +0=
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Nothing is moving at 40 cm/s.
The steel ball is initially moving at 80 cm/s.
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2.4kgcm/s
+ .060*50cm/s+.020*80cm/s
4.6+2.4
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The objects have a certain total momentum before collision, and a certain total momentum after the collision.
Your calculation would add the total momentum before the collision to the total momentum after. There is no point in doing that.
The key idea is that, ideally, the total momentum before is equal to the total momentum after the collision.
So you would calculate the total momentum beforce, and you would calculate the total momentum after. Then you would add the two.
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7kgcm/s
I don’t think I did this right at all but I don’t thinkthe momentum would be the same
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• What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
I don’t know
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