course Phy 201 ۋF͛{ˈ~sxassignment #000
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20:56:59 The Query program normally asks you questions about assigned problems and class notes, in question-answer-self-critique format. Since Assignments 0 and 1 consist mostly of lab-related activities, most of the questions on these queries will be related to your labs and will be in open-ended in form, without given solutions, and will not require self-critique. The purpose of this Query is to gauge your understanding of some basic ideas about motion and timing, and some procedures to be used throughout the course in analyzing our observations. Answer these questions to the best of your ability. If you encounter difficulties, the instructor's response to this first Query will be designed to help you clarify anything you don't understand. {}{}Respond by stating the purpose of this first Query, as you currently understand it.
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RESPONSE --> The purpose of the first Query is to understand basic ideas about motion and timing and I am to answer the following questions to the best of my ability and my instructor will help clarify anything that I do not understand.
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20:58:19 If, as in the object-down-an-incline experiment, you know the distance an object rolls down an incline and the time required, explain how you will use this information to find the object 's average speed on the incline.
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RESPONSE --> To find the average speed of the ball rolling down I would take the distance traveled and divide that by the time elapsed to calculate the average speed. confidence assessment: 2
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21:01:03 If an object travels 40 centimeters down an incline in 5 seconds then what is its average velocity on the incline? Explain how your answer is connected to your experience.
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RESPONSE --> average velocity= displacement / time elasped therefore, average velocity= 40 cm/ 5 sec = 8cm per sec. This is connected to my experience because I calculated the average speed in my experiment, and I can also calculate the average velocity of the object. confidence assessment: 2
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21:04:47 If the same object requires 3 second to reach the halfway point, what is its average velocity on the first half of the incline and what is its average velocity on the second half?
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RESPONSE --> The halfway point would be half of 40 cm which is 40/2= 20cm therefore 20cm/3 sec= 6.66 cm per sec for the average velocity of the first half, and the second half would be 20 cm/ (5sec-3sec=2sec) = 10cm per sec for the average velocity on the second half confidence assessment: 2
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21:08:55 Using the same type of setup you used for the first object-down-an-incline lab, if the computer timer indicates that on five trials the times of an object down an incline are 2.42 sec, 2.56 sec, 2.38 sec, 2.47 sec and 2.31 sec, then to what extent do you think the discrepancies could be explained by each of thefollowing: {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioningthe object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> a- timer only counts on a certain numerical basis, not to an actual value of .0001 b- human triggering could have hit late or early causing the timing to be inconsistent. c- the book could have misleading dips or wind could have an effect on the ball, or the ball itself could effect the timing of how long it takes to roll down. d-positioning the object can vary, you make think you released it in the correct position, but it could be exact, more to the left or more to the right causing the timing to be off e-human eye could be misleading on how early, exact, or late the ball has reached the end of the incline. confidence assessment: 2
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21:14:42 How much uncertainty do you think each of the following would actually contribute to the uncertainty in timing a number of trials for the object-down-an-incline lab? {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated bLine$(lineCount) =with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> a-the timer program can vary from interval to interval due to the specific numbers that are in the system because it is not based solely on elapsed time b- human triggering could be faster or slower from interval to interval c- time differences can be because of the timer program, human triggereing, positioning of the object, and human uncetanity. d- uncertainty from interval to interval can be because it was placed in a different positions each time instead of the same place e- time after time, the uncertainty of the human eye observing when the end of the incline is reached can differ it can be detected earlier or later interval after interval. confidence assessment: 2
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21:22:08 What, if anything, could you do about the uncertainty due to each of the following? Address each specifically. {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actualdifferences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> a- you really can't do anything about the timer program, since it is a program, just trust it! b-human triggering trying to be as precise as possible on the clicking c- be as precise on the program, clicking, placement, triggering, and judgement to proceed with appropiate timing d-try to position the object in the same place time after time e- try to be as certain as possible when judging when the object has reached the end of the incline. confidence assessment: 2
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21:23:14 According to the results of your introductory pendulum experiment, do you think doubling the length of the pendulum will result in half the frequency (frequency can be thought of as the number of cycles per minute), more than half or less than half?
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RESPONSE --> doubling the length of the pendulum would result in less than half the frequency. confidence assessment: 2
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21:27:41 Note that for a graph of y vs. x, a point on the x axis has y coordinate zero and a point on the y axis has x coordinate zero. In your own words explain why this is so.
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RESPONSE --> The x and y axis has the coordinate point zero because this is the orgin which choose objects to be postive or negative. confidence assessment: 2
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21:34:43 On a graph of frequency vs. pendulum length (where frequency is on the vertical axis and length on the horizontal), what would it mean for the graph to intersect the vertical axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the vertical axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> if the line goes through the vertical axis that means that it has a negative slope, the higher the frequency the smaller the pendulum length, the smaller the frequency the longer the length. confidence assessment: 2
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21:36:59 On a graph of frequency vs. pendulum length, what would it mean for the graph to intersect the horizontal axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the horizontal axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> if the graph intersected the horizontal axis it would have a positive slope meaning the smaller the length the smaller the frequency, the longer the length the higher the frequency. confidence assessment: 1
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21:38:35 If a ball rolls down between two points with an average velocity of 6 cm / sec, and if it takes 5 sec between the points, then how far apart are the points?
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RESPONSE --> average velocity= distance traveled/ time elasped therefore, 6 cm/sec= distance traveled / 5 sec , there fore 6 cm/sec / 5 sec = 1.2 cm The points are 1.2 cm apart from one another. confidence assessment: 2
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21:40:37 On the average the ball moves 6 centimeters every second, so in 5 seconds it will move 30 cm. {}{}The formal calculation goes like this: {}{}We know that vAve = `ds / `dt, where vAve is ave velocity, `ds is displacement and `dt is the time interval. {}It follows by algebraic rearrangement that `ds = vAve * `dt.{}We are told that vAve = 6 cm / sec and `dt = 5 sec. It therefore follows that{}{}`ds = 6 cm / sec * 5 sec = 30 (cm / sec) * sec = 30 cm.{}{}The details of the algebraic rearrangement are asfollows:{}{}vAve = `ds / `dt. We multiply both sides of the equation by `dt:{}vAve * `dt = `ds / `dt * `dt. We simplify to obtain{}vAve * `dt = `ds, which we then write as{}`ds = vAve *`dt.{}{}Be sure to address anything you do not fully understand in your self-critique.
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RESPONSE --> i understand this calculation of how to find how much a ball will roll in 5 seconds by multiplying the seconds times the distance it travels (6 cm * 5 sec= 30cm/sec) self critique assessment: 2
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21:42:09 You were asked to read the text and some of the problems at the end of the section. Tell me about something in the text you understood up to a point but didn't understand fully. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> During assignment 1 we were not asked to read any material I am confused about this question, can you please respond back to me on this one!! confidence assessment: 1
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21:46:09 Tell me about something in the problems you understand up to a point but don't fully understand. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> The only problems that I had difficultly with were during the fitting the best line experiments. I had questions for the parts that asked for the y coordinate and the y intercept, I really did not know what to put in those answer, but I put the y coordinate that I would use to find the y intercept, and then later on in the experiment I used that ycoordinate to find the y intercept. confidence assessment: 2
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