Assignment 4

#$&*

course phy 201

sep. 27 6am

Assignment 4At clock time t = 7 sec, a ball rolling straight down a hill is moving at 6 m/s and is 47 m from the top of the hill. It accelerates uniformly at a rate of .6 m/s/s until clock time t = 17 sec. What is its velocity at this point and what is its average velocity during this time? How far is it from the starting point at t = 17 sec?

V =6m/sec +.6m/sec^2*10sec

V =12m/s

12m/s +6m/s /2 =9m/s =ave. vel.

47m+6m/s(10s) = ½ *6m/s^2(10^2)

X= 137m

"

&#Your work looks very good. Let me know if you have any questions. &#