Phy 231
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
The average velocity is equal to 2m/.64 seconds which equals 3.125m/s. Because the initial velocity was 0 because it was at rest, the final velocity is double the average which equals 6.25m/s. The acceleration is equal to 6.25-0 over .64s which equals an acceleration of 9.8m/s^2.
• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
At 5 meters, the average velocity is equal to 4.76m/s. The acceleration would be equal to 9.52 over 1.05 seconds which would equal 9.1m/s^2. This number is close, but slightly different than the value from above.
• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
I would say that these numbers for the most part are relatively close to the value of the acceleration of gravity. If you used the formula given in the notes for small slopes, that acceleration is equal to gravity times the slope, then both of these would equal the acceleration of gravity because the slope would be straight up and it would just be gravity taking place on the ball being dropped.
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15 min.
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&#Your work looks very good. Let me know if you have any questions. &#