Phy 231
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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15 min
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
The pulley will have one side with a weight of 5*9.8 which equals 49N and the other side with a weight of 6*9.8 which equals 58.8N. The side with the 58.8N is in the positive direction while the other side is in the negative direction. The net force on the system is the sum of the two forces which equal 58.8+-49 which equals a net force of 9.8N. The magnitude will then be equal to the 9.8N divided by the 11kg which equals .89m/s^2 directed on the side with more weight.
• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
using the formula of vf = v0 + a * `dt then vf=1.8m/s+-.89*1 the final velocity will equal .91m/s, which shows the object is slowing down.
• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
They are in opposite directions and the system will slow down until it reaches a point of equilibrium.
&#This looks very good. Let me know if you have any questions. &#