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Phy
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
• Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The velocity would go up the y axis and the time would go down the x axis.
The slope of the graph would be increases and the graph would be increasing
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• Sketch a straight line segment between these points.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
the straight line segment would go upward and to the right
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• What are the rise, run and slope of this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The rise would be 30cm/sec
The run would be 5sec
The slope would be 6cm/sec/sec
@& good*@
The rise would be 3
The run would be 5
The slope would be 3/5 or .6
@& I'm not sure what these calculations correspond to. You haven't included any units or explanations.*@
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• What is the area of the graph beneath this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
area= ave.ht * width
5m/s * 5s = 125m
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@& ave ht * width is right. However the y coordinate of this graph goes from 10 cm/s to 40 cm/s. It is alway's 'higher' than 5 cm/s, so 5 cm/s doesn't represent the average height of this region.*@
*#&!*#&!
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