#$&*
course Phy 242
March 22 around 6pm.
Brief Rubberband-Chain Experiment 1A________________________________________
You will ultimately need to a chain of at least 100 rubber bands. For the present experiment you can get by with about half that. This is something you can do any time your hands are free. It takes most people 20 minutes or less to chain 100 rubber bands.
Use a chain at least 3 meters long. Fix one end of the chain so that it remains stationary. Hold the other end at the same level as the fixed end, pulling your end back until the middle of the chain hangs down about a foot below the ends. Note where your end is so you can later measure the distance between the two ends.
Pluck your end and watch the pulse travel down the chain and back. Hold your end stationary so that the pulse can reflect down the chain and back, returning a number of times.
... dominoes and strain, or strain ension to support full soft drink bottle
Using the TIMER program, or a clock that displays seconds, take the best data you can to determine the speed of the pulse as it travels back and forth on the chain. The longer the interval you time, the less the inevitable uncertainty in your measurement as a percent of the interval, so you should time as many return pulses as possible.
Give your data, your explanation, and your conclusion about the speed of the pulse:
****
0.375
0.437
0.360
0.437
0.484
0.438
0.391
0.359
0.359
0.407
0.359
0.375
0.391
0.328
0.390
0.375
0.407
I used the TIMER program and clicked every time a pulse hit the other end AND my end. I tried to click as long as I could see the pulse until it got so small I couldn’t tell. Interval was 6.297 seconds.
#$&*
Repeat, pulling a little harder so that the center of the chain hangs only about half as far below the ends as in your preceding trial. This will increase the length of the chain.
Give your data, your explanation, and your conclusion about the speed of the pulse:
****
0.359
0.281
0.297
0.313
0.296
0.282
0.281
0.281
0.297
0.266
0.25
0.281
0.266
0.343
0.25
0.266
0.281
0.328
0.266
I once again used the TIMER program and just pulled the chain and made it longer. Obviously, the pulses were faster than the first trial. I went as long as I could again, until it got too “wiggly” to tell the pulses. Interval was 5.125 seconds.
#$&*
Repeat once more, once more increasing the length of the chain, by about as much as you did before:
Give your data, your explanation, and your conclusion about the speed of the pulse:
****
0.218
0.219
0.266
0.234
0.266
0.234
0.25
0.25
0.266
0.25
0.25
0.265
0.266
0.219
0.25
0.25
0.218
I pulled the chain to where it was pretty much a straight line. It was pulled tight and the pulses were faster than before. I watched as long as I could. Interval was 3.953 seconds.
#$&*
Halve the length of the chain by folding it back on itself (so for example, if you had a 4 m chain, you would now have a 'doubled' chain 2 m long). Repeat once more (so if you started with a 4 m chain, you would now have a 'quadrupled' chain 1 meter long).
Hang a plastic bag or a plastic bottle containing an 8 ounce cup of water from this chain and measure the length of the chain. If you don't have an 8 ounce cup, half of a bottle of water will do (for a bottle with capacity between 16 ounces and 24 ounces) will do. Then add an equal amount of water and measure the length again.
Report your data (including how much water was used).
Based on your data, what was the percent change in the length of the chain, between the two measurements?
****
I used 8 ounces of water in a Ziploc bag and hung the bag on the end of the chain, in a vertical manner. The starting measurement of the “quadrupled” chain was approx. 30 inches. After I added the plastic bag, the measurement was 36 inches or 3 feet. There was a 6 inch difference, so 20% difference?!
#$&*
What was the percent change, per gram of additional water? (8 ounces is roughly 230 grams)?
****
8 oz(230g) resulted in 6 inch difference.
Therefore, 1 oz(28g) will result in approx. 0.75 inches difference.
About 75-80%?!
#$&*
@& That would be .75 inches per ounce.
.75 inches is about 2.5% of the original length, so you would have about 2.5% per ounce.
How much per gram?*@
What was the percent change, per Newton of additional water weight?
****
#$&*
@& What was the weight of the water in Newtons?
You had a 20% change in length. How much is this per Newton?*@
*** File was originally submitted on 3/21 or 3/22, was critiqued by failed to post. ***
#$&*
course Phy 242
March 22 around 6pm.
Brief Rubberband-Chain Experiment 1A________________________________________
You will ultimately need to a chain of at least 100 rubber bands. For the present experiment you can get by with about half that. This is something you can do any time your hands are free. It takes most people 20 minutes or less to chain 100 rubber bands.
Use a chain at least 3 meters long. Fix one end of the chain so that it remains stationary. Hold the other end at the same level as the fixed end, pulling your end back until the middle of the chain hangs down about a foot below the ends. Note where your end is so you can later measure the distance between the two ends.
Pluck your end and watch the pulse travel down the chain and back. Hold your end stationary so that the pulse can reflect down the chain and back, returning a number of times.
... dominoes and strain, or strain ension to support full soft drink bottle
Using the TIMER program, or a clock that displays seconds, take the best data you can to determine the speed of the pulse as it travels back and forth on the chain. The longer the interval you time, the less the inevitable uncertainty in your measurement as a percent of the interval, so you should time as many return pulses as possible.
Give your data, your explanation, and your conclusion about the speed of the pulse:
****
0.375
0.437
0.360
0.437
0.484
0.438
0.391
0.359
0.359
0.407
0.359
0.375
0.391
0.328
0.390
0.375
0.407
I used the TIMER program and clicked every time a pulse hit the other end AND my end. I tried to click as long as I could see the pulse until it got so small I couldn’t tell. Interval was 6.297 seconds.
#$&*
Repeat, pulling a little harder so that the center of the chain hangs only about half as far below the ends as in your preceding trial. This will increase the length of the chain.
Give your data, your explanation, and your conclusion about the speed of the pulse:
****
0.359
0.281
0.297
0.313
0.296
0.282
0.281
0.281
0.297
0.266
0.25
0.281
0.266
0.343
0.25
0.266
0.281
0.328
0.266
I once again used the TIMER program and just pulled the chain and made it longer. Obviously, the pulses were faster than the first trial. I went as long as I could again, until it got too “wiggly” to tell the pulses. Interval was 5.125 seconds.
#$&*
Repeat once more, once more increasing the length of the chain, by about as much as you did before:
Give your data, your explanation, and your conclusion about the speed of the pulse:
****
0.218
0.219
0.266
0.234
0.266
0.234
0.25
0.25
0.266
0.25
0.25
0.265
0.266
0.219
0.25
0.25
0.218
I pulled the chain to where it was pretty much a straight line. It was pulled tight and the pulses were faster than before. I watched as long as I could. Interval was 3.953 seconds.
#$&*
Halve the length of the chain by folding it back on itself (so for example, if you had a 4 m chain, you would now have a 'doubled' chain 2 m long). Repeat once more (so if you started with a 4 m chain, you would now have a 'quadrupled' chain 1 meter long).
Hang a plastic bag or a plastic bottle containing an 8 ounce cup of water from this chain and measure the length of the chain. If you don't have an 8 ounce cup, half of a bottle of water will do (for a bottle with capacity between 16 ounces and 24 ounces) will do. Then add an equal amount of water and measure the length again.
Report your data (including how much water was used).
Based on your data, what was the percent change in the length of the chain, between the two measurements?
****
I used 8 ounces of water in a Ziploc bag and hung the bag on the end of the chain, in a vertical manner. The starting measurement of the “quadrupled” chain was approx. 30 inches. After I added the plastic bag, the measurement was 36 inches or 3 feet. There was a 6 inch difference, so 20% difference?!
#$&*
What was the percent change, per gram of additional water? (8 ounces is roughly 230 grams)?
****
8 oz(230g) resulted in 6 inch difference.
Therefore, 1 oz(28g) will result in approx. 0.75 inches difference.
About 75-80%?!
#$&*
@& That would be .75 inches per ounce.
.75 inches is about 2.5% of the original length, so you would have about 2.5% per ounce.
How much per gram?*@
What was the percent change, per Newton of additional water weight?
****
#$&*
@& What was the weight of the water in Newtons?
You had a 20% change in length. How much is this per Newton?*@
03-22-2011
#$&*
course Phy 242
March 22 around 6pm.
Brief Rubberband-Chain Experiment 1A________________________________________
You will ultimately need to a chain of at least 100 rubber bands. For the present experiment you can get by with about half that. This is something you can do any time your hands are free. It takes most people 20 minutes or less to chain 100 rubber bands.
Use a chain at least 3 meters long. Fix one end of the chain so that it remains stationary. Hold the other end at the same level as the fixed end, pulling your end back until the middle of the chain hangs down about a foot below the ends. Note where your end is so you can later measure the distance between the two ends.
Pluck your end and watch the pulse travel down the chain and back. Hold your end stationary so that the pulse can reflect down the chain and back, returning a number of times.
... dominoes and strain, or strain ension to support full soft drink bottle
Using the TIMER program, or a clock that displays seconds, take the best data you can to determine the speed of the pulse as it travels back and forth on the chain. The longer the interval you time, the less the inevitable uncertainty in your measurement as a percent of the interval, so you should time as many return pulses as possible.
Give your data, your explanation, and your conclusion about the speed of the pulse:
****
0.375
0.437
0.360
0.437
0.484
0.438
0.391
0.359
0.359
0.407
0.359
0.375
0.391
0.328
0.390
0.375
0.407
I used the TIMER program and clicked every time a pulse hit the other end AND my end. I tried to click as long as I could see the pulse until it got so small I couldn’t tell. Interval was 6.297 seconds.
#$&*
Repeat, pulling a little harder so that the center of the chain hangs only about half as far below the ends as in your preceding trial. This will increase the length of the chain.
Give your data, your explanation, and your conclusion about the speed of the pulse:
****
0.359
0.281
0.297
0.313
0.296
0.282
0.281
0.281
0.297
0.266
0.25
0.281
0.266
0.343
0.25
0.266
0.281
0.328
0.266
I once again used the TIMER program and just pulled the chain and made it longer. Obviously, the pulses were faster than the first trial. I went as long as I could again, until it got too “wiggly” to tell the pulses. Interval was 5.125 seconds.
#$&*
Repeat once more, once more increasing the length of the chain, by about as much as you did before:
Give your data, your explanation, and your conclusion about the speed of the pulse:
****
0.218
0.219
0.266
0.234
0.266
0.234
0.25
0.25
0.266
0.25
0.25
0.265
0.266
0.219
0.25
0.25
0.218
I pulled the chain to where it was pretty much a straight line. It was pulled tight and the pulses were faster than before. I watched as long as I could. Interval was 3.953 seconds.
#$&*
Halve the length of the chain by folding it back on itself (so for example, if you had a 4 m chain, you would now have a 'doubled' chain 2 m long). Repeat once more (so if you started with a 4 m chain, you would now have a 'quadrupled' chain 1 meter long).
Hang a plastic bag or a plastic bottle containing an 8 ounce cup of water from this chain and measure the length of the chain. If you don't have an 8 ounce cup, half of a bottle of water will do (for a bottle with capacity between 16 ounces and 24 ounces) will do. Then add an equal amount of water and measure the length again.
Report your data (including how much water was used).
Based on your data, what was the percent change in the length of the chain, between the two measurements?
****
I used 8 ounces of water in a Ziploc bag and hung the bag on the end of the chain, in a vertical manner. The starting measurement of the “quadrupled” chain was approx. 30 inches. After I added the plastic bag, the measurement was 36 inches or 3 feet. There was a 6 inch difference, so 20% difference?!
#$&*
What was the percent change, per gram of additional water? (8 ounces is roughly 230 grams)?
****
8 oz(230g) resulted in 6 inch difference.
Therefore, 1 oz(28g) will result in approx. 0.75 inches difference.
About 75-80%?!
#$&*
@& That would be .75 inches per ounce.
.75 inches is about 2.5% of the original length, so you would have about 2.5% per ounce.
How much per gram?*@
What was the percent change, per Newton of additional water weight?
****
#$&*
@& What was the weight of the water in Newtons?
You had a 20% change in length. How much is this per Newton?*@
03-22-2011