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course Phy 241
121107_LAB_DATA`q001. Give your data from today's lab activities.
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Steel ball, marble accelerated towards one another. Collision was observed.
Ramp 61 cm long.
Relative velocity:
When the marble travels 44 cm, steel ball travels 17cm, the marble stops the motion of the steel ball.
Vs1(vel of steel ball before collision) = 17/44 *Vm1
Observations:
All measurements in cm.
Trial #, distance marble traveled, distance steel ball traveled.
1, 32cm, 29cm.
2, 35, 26.
3, 37, 24.
4, 35, 26.
5, 39, 22.
6, 28, 33.
7, 43, 18.
Analyzed data using:
Mm = mass of marble = .22 kg.
Ms = Mass of steel = .665 kg.
Ms*Vs1 + Mm*Vm1 = Ms*Vs2 + Mm*Vm2.
When marble stops ball, Vs2 = 0.
Ms * 17/44* Vm1 + Mm*Vm1 = Mm*Vm2.
Ms/Mm * 17/44 * Vm1 + Vm1 = Vm2.
Vm1*(Ms/Mm * 17/44 + 1) = Vm2.
Plugging numbers in:
2.168* Vm1 = Vm2.
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It appears that your observed velocity ratio (marble to ball) is about 2.6, and the mass ratio is very close to 1/3.
According to momentum conservation, for this collision, in which the mabls stops the ball, should the velocity ratio and the mass ratio by in this proportion?
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