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course Phy 122
Not sure if I am picturing the problem correctly, but had to draw it out a couple of times.
Question: query introset plug of water from cylinder given gauge pressure, c-s hole area, length of plug.
Explain how we can determine the velocity of exiting water, given the pressure difference between inside and outside, by considering a plug of known cross-sectional area and length.
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Your Solution:
If I remember correctly, you need to find the force on the plug. Since Force is Pressure * Area. If c-s hole area is given, I would use that. So, water having a density of 1000kg/m^3, P = (rho)g(gravity 9.8m/s^2)h(depth). Now we have the pressure. From this formula we can also get the volume which would be Ah or the Area multiplied by the depth. The volume and density multiplied together, gives us our mass. For the force, we will use it to find KE or kinetic energy which is W=Fd(distance) which in this case we return to the measurement of our plug. So now we have our J measurement of kinetic energy, to get the velocity we use KE = ½ (m)(v)^2. All gets plugged into the equation to get the velocity, if I am picturing the problem correctly.
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I believe you're seeing this very well. Good description of the process.
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