course Mth 158
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3. The solution set of the equation (x-3)(3x+5)=0 is {3, -5/3}
5. To complete the square of the expression x^2+5x, you would add the number 5/2^2.
8. T or F - If the discriminant of a quadratic equation is positive, then the equation has two solutions that are negatives of one another. This is true.
Solve by factoring --
11. x^2-25=0 x^2 - 25 = 0 Solution set is
(x+5)(x-5) = 0 {-5, 5}
x+5 = 0 x-5 = 0
-5 -5 +5 +5
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x = -5 x = 5
14. ??
17. 3t^2 - 48 = 0
3(t^2-16)=0
3(t+4)(t-4) = 0
t = 4, -4 Solution set is {4, -4}
20. x(x+4) = 12
x+4x = 12
-4 = -4
x = 8
Also x = 0
23. 6(p^2 - 1) = 5p
6p^2 - 6 = 5p
6p^2 - 5p - 6 = 0
(3p + 2)(2p - 3) = 0
p = -2/3 p = 3/2
{-2/3, 3/2}
26. x + 12/x = 7
x + 12/x = 7
x + 12 = 7 + 12 ??
If you multiply both sides of x + 12/x = 7 by x you get x^2 + 12 = 7 x. This is a quadratic equation. Rearrange to standard for x^2 - 7 x + 12 = 0, and you can easily solve by factoring.
Solve by the square root method.
29. x^2 = 25 {-5, 5}
32. (x-1)^2 = 4
2x-1 = 4 {2, -2}
You get (x-1) = +-2 .
If x-1 = 2 then x = 3.
If x-1 = -2 then x = -3.
What number should be added to complete the square of each expression?
36. x^2 - 4x -4/2 = -2^2 = 4 the answer is 4
38. x^2 - 1/3 x -1/3 divided by 2/1 = -1/3 times 1/2 = -1/6 = 1/36
Solve by completing the square
41. x^2 + 4x = 21
x^2 + 4x + 4 = 21 + 4
(x-2)^2 = 25
x + 2 = the square root of 25
x + 2 = 5
x = -2 + 5 = x = 3, x = -7 {-7, 3}
x + 2 = 5 gives you x = 3
x + 2 = -5 gives you x = -7.
Be sure to show these details.
44. ???
Use the quadratic formula to find real solutions if any.
47. x^2 - 4x + 2 = 0
(x+2)(x-2) = 0
x + 2 = 0 x - 2 = 0
- 2 -2 +2 +2
x = -2 x = 2 {-2, 2}
50. x^2 + 6x + 1 = 0
(x-3)(x+3) = 0
x - 3 = 0 x - 3 = 0
+3 +3 +3 +3
x = -3 x = 3 {-3, 3}
You used factoring on this problem and the last. You need to use the quadratic formula.
52. ??
55. 4x^2 = 1 - 2x 4x^2 + 2x - 1 = 0 ?????
58. ??
61. 3/4x^2 - 1/4x - 1/2 = 0
4(3/4x^2 - 1/4x - 1/2) = (0, 4)
3x^2 - x - 2 = 0
Good so far. Use the quadratic formula.
64. 4 + 1/x - 1/x = 0 4 + 1/x = 0
Find real solutions if any - use quadratic formula and calculator - express solutions rounded to 2 decimal places.
67. x^2 - 4.lx + 2.2 = 0
x = (-4.1) + inside square root is -4.1^2 - 4.(1)(2.2)/2(1)
___________________________
2(1)
= 4.1 + (inside square root 16.81 - 8.8 / 2 = 4.1 + inside square root 8.01 with both being divided by 2
The form in which you should express this calculation in 'typewriter notation' is
[ -(-4.1) +- sqrt( (-4.1)^2 - 4 * 1 * 2.2 ) ] / (2 * 1) =
[4.1 +- sqrt(16.81 - 8.8) ] / 2 =
[4.1 +- sqrt(8.01)] / 2.
You can then go on to calculate the two numbers
[4.1 + sqrt(8.01)] / 2 and
[4.1 - sqrt(8.01)] / 2,
both to an appropriate number of significant figures.
70. ??
72. Pix^2 + Pix - 2 = 0
2Pix^2 - 2 = 0
pi x^2 and pi x are not like terms, one being an x term and the other an x^2 term.
Use the quadratic formula.
75. x^2 - 5 = 0 x^2 = 5 x = +then the square root of 5 -- the solutions is (-square root of 5, and square root of 5)
78. ??
81. 2 + z = 6z^2
6z^2 - z - 2
(3z-2)(2z+1)
3z - 2 = 0 or 2z + 1 = 0
z = 2/3 or z = 1/2
84. ??
87. 2x^2 - 6x + 7 = 0 a = 2 b = -6 c = 7
b^2 - 4ac = (-6)^2 - 4(2)(7) = 36 - 56 = -20 no real solution
90. 25x^2 - 20x + 4 = 0
a = 25 b = -20 c = 4
b^2 - 4ac = (-20)^2 - 4(25)(4) = 400 - 116 = 284
93. Dimensions of a window- The area of the opening of a rectangular window is to be 143 sq. ft. If the length is to be 2 ft. more than the width, what are the dimensions?
w(w+2) = 143 w^2 + 2w - 143 = 0 (w + 13)(w - 11) = 0 w = -13 w = 11 width is 11 and length is 13
96. ??
98. ??
97. An open box is to be constructed from a sq. piece of sheet metal by removing a square of side 1 foot from each corner and turning up the edges. If the box is to hold 4 cubic feet, what should the dimensions of the sheet metal be? (x-2)(x-2)(1) = 4
x^2 - 4x + 4 = 4
x^2 - 4x = 0
x(x-4) = 0 x = 0 or x = 4
100.??
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You are doing well here. See my notes to clarify a few point, and let me know if you have questions.