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Mth 279
Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Assignment #3
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I am working on assignment #3. In the qa document and the notes, the first lines are:
y ' + t y = 0 has solution y = e^(-t).
If y = e^(-t) then y ' = -t e^(-t) so that
y ' + t y becomes -t e^-t + t e^-t, which is zero.
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I was careless with that first example, which should have read
y ' + t y = 0 has solution y = e^(-t^2 / 2).
If y = e^(-t^2 / 2) then y ' = -t e^(-t^2 / 2) so that
y ' + t y becomes -t e^(-t^2 / 2) + t e^(-t^2 / 2), which is zero.
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How did you get that? Where does the e^(-t) come from?
The book just says to solve y' = -p(t)y, we need to find a function y(t) whose derivative is equal to -p(t) times y(t)
Does this mean y' + y = e^(y) ?
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Check my note. I apologize for the error in my document, which has been revised.
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