phy 201
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> : v0 = 0 ds = 2 t = .64
Vavg. = 2/.64 = 3.125 Vf= 6.25 A = 6.25/.64 = 9.76
• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> : No, this 1 is a little off cause 5 / 1.05 = 4.76 so 4.76 is the Vavg. To get Vf take 4.76*2 = 9.52 then we can get A by 9.52/1.05 = 9.07 which is not 9.80m/s^2 like gravity is.
• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> : The first one is but as you see from the results the second one is off by some.
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30 min
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&#Good responses. Let me know if you have questions. &#