Your 'cq_1_08.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball is tossed upward at 15 meters / second from a height of 12 meters above the ground. Assume a uniform downward acceleration of 10 m/s^2 (an approximation within 2% of the 9.8 m/s^2 acceleration of gravity).
• How high does it rise and how long does it take to get to its highest point?
• How fast is it then going when it hits the ground, and how long after the initial toss does it first strike the ground?
• At what clock time(s) will the speed of the ball be 5 meters / second?
• At what clock time(s) will the ball be 20 meters above the ground?
• How high will it be at the end of the sixth second?
answer/question/discussion: ->->->->->->->->->->->-> :
Height= 11.25
V= v0+at
0=15+10t =15/10 t=1.5
V = v0+at 5 = 15+10t = 10 = 10t = 10/10= 1 sec
270 meters after 6 seconds.
For some reason I was completely lost doing this I can’t figure out if I doing this right or not. And I don’t know if the answers I did find are right or not
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1hr
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