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Phy 121
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
y = v0t + 1/2at^2
2m = 0 + 1/2 a (.64s)^2
2m = .2048s^2 * a
a = 9.77 m/s^2
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• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
y = v0t + 1/2at^2
5m = 0 + 1/2a (1.05s)^2
5m = .55s^2 * a
a = 9.07 m/s^2
No, the acceleration would be slightly different.
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• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
No, the acceleration values are slightly different than 9.8 m/s^2.
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&#Very good responses. Let me know if you have questions. &#