course Mth173
Quiz 2course Mth 173
Justin Funk Quiz 2
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Problem #8
At what average rate is the temperature of the potato changing between clock times t = 17.1 and t = 17.2 seconds seconds? At (t) = 17.1 the temperature is 80.005. At (t) = 17.2 the temperature is 79.99. Therefore the slope or average rate of change is .006/-.1 =-.06
that would be -.06
At what average rate is the temperature of the potato changing between clock times t = 17.1 and t = 17.11 seconds? At (t) = 17.1 the temperature is 80.005. At (t) = 17.11 the temperature is 80.003. Therefore the slope or average rate of change is .002/-.01 = -.2.
At what average rate is the temperature of the potato changing between clock times t = 17.1 and t = 17.101 seconds? At (t) = 17.1 the temperature is 80.0052. At (t) = 17.101 the temperature is 80.005. Therefore the slope or average rate of change is .0002/-.001 = -.2.
What do you estimate is the rate at which temperature is changing at clock time t = 17.1 seconds? R= .0392
Your rates are calculated only to one significant figure, which is not sufficient to show the pattern of the changes in the average rates.
You need enough significant figures in your calculations of temperatures to give the changes in temperature a sufficient number of significant figures.
A sufficient number is at least enough to reveal differences with previous average rates.
The rate at which the Celsius temperature of a hot potato placed in a room is given by Rate = .041 * 2- .0038 t, where R is rate of change in Celsius degrees per second and t isclock time in seconds. How much temperature change do you estimate would occur
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between t = 17.1 and t = 34.2 seconds? R=.041*2-.0038(17.1)=80.005
R=.041*2-.0038(34.2) = 15.578. Therefore when you take 80.005 and subtract 15.578 from it you get the temp. change of to be 64.427.
If you subtract one rate of change from another, you get the change in the rate of change, not the change in the temperature.
If you want to get the change in temperature from rate of change information, find the average rate of change and multiply this by the change in clock time.
You don't indicate where the 80.005 and 15.578 come from or why you subtracted them.
You did the first part right, but not with sufficient precision.
It's not clear how you did the second part. Please see my notes and submit a revision.
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