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phy210
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
• What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The clocked time at the midpoint is 9 ((13+5)/2)
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• What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The velocity at this point is 28 cm/sec this was calculated by adding the finial and starting velocity they divide the result by two ((40+16)/ 2)
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• How far do you think the object travels during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
the object travelled at a average rate of 28 cm/sec this was calculated by adding the finial and starting velocity they divide the result by two ((40+16) /2) over a time interval of 8 sec (13sec – 5sec) so the distance (d) traveled is average velocity multiplied by time;
d = 28*8 = 224cm
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• By how much does the clock time change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The clock changes from 5 sec to 13 sec so it changes by 8 sec over the interval
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• By how much does velocity change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The velocity changes from 16 cm/sec to 40cm/sec so it changes by 24cm/ sec over the interval
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• What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
the average rate of change of the velocity (acceleration) is given bellow;
= change in velocity/ change in time
= (24 cm/sec) /8 sec
=3 cm/sec2
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• What is the rise of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
the rise of the graph between the points is 24cm/sec (40-16)
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• What is the run of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
the run of the graph between the points is 8 sec (13-5)
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• What is the slope of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
the slope is given by rise/run
slope = 24/8
Slope = 3 cm/sec2
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• What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The slope of the graph gives the acceleration of the object between the two points
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• What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
the average rate of change of the velocity (acceleration) is given bellow;
= change in velocity/ change in time
= (24 cm/sec) /8 sec
=3 cm/sec2
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*#&!
&#Very good responses. Let me know if you have questions. &#