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PHY 201
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_02.2_labelMessages **
The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t
= 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16
cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
M= [(x1+ x2)/2] , [(y1 + y2)/2] = [(5+13)/2], [(16cm/s + 40cm/s)/2] = (9 sec, 28cm/s)
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What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Since the graph is velocity vs. clock time, 28cm/s is the velocity at the midpoint interval.
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How far do you think the object travels during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
`ds = vAve * `dt = 28cm/s * (13sec-5sec) = 28cm/s * 8 sec = 224cm * sec /sec = 224cm
`ds =224cm
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By how much does the clock time change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
13 sec - 5 sec = 8 seconds
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By how much does velocity change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
40cm/s - 16cm/s = 24 cm/sec
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What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
aAve = 24cm/s / 8 sec = 3cm/s /second
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What is the rise of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The rise = 'dv, so 24 units. 40 -16 =24
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What is the run of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Run = 'dt, so 8 units. 13 - 5 = 8 units
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What is the slope of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
m = rise/run, so m=24/8 or m=3.
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@&
Rise, run and slope all have units, which in this case are consistent with the corresponding units of your previous calculations.
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What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The slope of the graph tells me that the object is increasing the distance it travels in cm/sec for
each second that passes.
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What is the average rate of change of the object's velocity with respect to clock time during this
interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
24cm/sec / 8sec = 3cm/sec/sec
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*#&!
&#Your work looks good. See my notes. Let me know if you have any questions. &#