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course PHY 201
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Asst_8_Week4_Quiz1_vs16A projectile leaves the edge of a table and, while traveling horizontally at a constant velocity, falls freely a distance of 74 cm to the floor. It travels a horizontal distance of 5.7 cm during its fall. If its vertical acceleration is 980 cm/s2, how long does it take to fall and what is its horizontal velocity during the fall?
Known variables:
a=980cm/s^2
vertical_`ds=74cm
v0=0
horizontal_`ds= 5.7cm
To find vertical clocktime I used:
`ds = v0* `dt + .5(a)* `dt^2
74cm = 0m/s*`dt + .5(980cm/s^2)*`dt^2
74cm = (490cm/s^2)*`dt^2
74cm/ 490cm/s^2 = `dt^2
`dt= sqrt(74cm/490cm/s^2)
`dt (apx)= .15s (positive since clocktime is progressing)
At the edge of the table, the position is 0 with regard to the .15 second of free fall time. The final position is 5.7cm from the edge of the table.
vAve= `ds/`dt
vAve= 5.7cm / .15sec
vAve= 38cm/s
&#Your work looks very good. Let me know if you have any questions. &#