course Phy 201
I forgot to include my name and stuff when I submitted the form earlier--instead of re-typing everything I did it like this. I hope it is acceptable.
identifyingInfo: Submitting Assignment: Energy Conversion 1
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Slope and vertical intercept of straight-line approximation to sliding distance vs. energy, units of slope and vertical intercept, description of the graph and closeness to line, any indication of curvature::
.49, 3.8 Slope has no units; the vertical intercept is in ergs? All but the last data point cluster near the line. Very little curvature, if any, is is apparent. If there is curvature, it would be downward concavity., 1.196, about 14 no units for slope, ergs for vertical intercept Fairly close until the points get higher on the graph concave up
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How far and through what angle did the block displace on a single trial, with rubber band tension equal to the weight of two dominoes?
0, 0 The first number is how far in cm the dominos moved and the second is the angle degree that the dominos spinned during the cm move.
5 trials, distance in cm then rotation in degrees, with rubber band tension equal to the weight of two dominoes:
0 0 0 0 0 The dominos moved none during these trials.
Rubber band lengths resulting in 5 cm, 10 cm and 15 cm slides:
8.0, 8.5, 8.9 These are the lengths of the rubber band that made the dominos move 5, 10, and 15 cm respectively.
5 trials, distance in cm then rotation in degrees, with rubber band tension equal to the weight of four dominoes:
3.2cm, 0 degrees 3.32 cm, 10 degrees 3.35 cm, 0 degrees 3.25 cm, 20 degrees 3.31 cm, 15 degrees The distances were fairly the same regardless of the distance the dominos spinned.
5 trials, distance in cm then rotation in degrees, with rubber band tension equal to the weight of six dominoes:
5.62 cm, 25 degrees 5.65 cm, 20 degrees 6.25 cm, 10 degrees 5.74 cm, 20 degrees 6.00 cm, 15 degrees The slide distances were more scattered this time, possibly because the dominos spinned more during these trials than during the last.
5 trials, distance in cm then rotation in degrees, with rubber band tension equal to the weight of eight dominoes:
7.95cm, 10 degrees 8.62 cm, 0 degrees 8.42 cm, 10 degrees 8.38 cm, 20 degrees 7.98 cm, 20 degrees More scattered slide distances again.
5 trials, distance in cm then rotation in degrees, with rubber band tension equal to the weight of ten dominoes:
10.90 cm, 10 degrees 10.93 cm, 5 degrees 11.03 cm, 0 degrees 10.96 cm, 10 dgrees 10.85 cm, 15 degrees Far less scattered
Rubber band length, the number of dominoes supported at this length, the mean and the standard deviation of the sliding distance in cm, and the energy associated with the stretch, for each set of 5 trials:
7.40, 2, 0, 0 7.71, 4, 3.286, .06024 8.04, 6, 5.852, .2681 8.12, 8, 8.27, .2931 8.45, 10, 10.93, .07631
Lengths of first and second rubber band for (first-band) tensions supporting 2, 4, 6, 8 and 10 dominoes:
7.40, 7.20 7.71, 7.6 8.04, 7.95 8.12, 8.10 8.45, 8.40
Mean sliding distance and std dev for each set of 5 trials, using 2 rubber bands in series:
2.256, .03646 4.904, .03049 8.776, .1604 17.81, .1176 19.86, .09839
1-band sliding distance and 2-band sliding distance for each tension:
0, 2.256 3.286, 4.904 5.582, 8.776 8.27, 17.81 10.93, 19.86
Slope and vertical intercept of straight-line approximation to 2-band sliding distance vs. 1-band sliding distance, units of slope and vertical intercept, description of the graph and closeness to line, any indication of curvature:
1.96, -1.56 no units for slope; ergs for vertical intercept The points cluster very closely around the line; the only exception is the second point. I don't think there is any curvature at all in this graph.
Discussion of two hypotheses: 1. The sliding distance is directly proportional to the amount of energy required to stretch the rubber band. 2. If two rubber bands are used the sliding distance is determined by the total amount of energy required to stretch them.
I definately think the data supports the hypothesis: as the length increases, so does the energy (if force is constant).
How long did it take you to complete this experiment?
2 hours
Optional additional comments and/or questions:
Return to the form.
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You'll go blind trying to read it if the document is posted to your access page in this format. I might fare better--I know what I'm looking for. I've looked over your data and it looks good, but if I need to go back and spot something it's sometimes difficult to find it.
Take a few minutes and insert at the beginning of each line which describes the information, and
at the end. Don't do anything to the lines containing the information you put into the program, except put some line breaks in there so the data appears in separate lines as intended. Then send it using the Submit Work form.