course PHY 201 ???m??????x???assignment #001001.
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21:06:12 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> It is the square root of the average squared deviation from the mean confidence assessment: 3
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21:09:36 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> It is all a matter of how you perceive the data points. The more scattered the points are the more varied different peoples answers will be. You have to guess what line would be the least distance away from all of the points. confidence assessment: 3
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21:11:00 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> Velocity is motion in a direction. It is measured in terms such as mph, cm per second, etc. A rate is how fast something is traveling and velocity is a rate in these terms confidence assessment: 3
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21:12:22 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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RESPONSE --> I understand the definition of rate now, I wasnt thinkink about it in broad enough terms self critique assessment:
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21:14:54 Given average speed and time interval how do you find distance moved?
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RESPONSE --> d=rt d=dr*dt divide the rate by the time confidence assessment: 3
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21:15:19 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> I meant to put times not divide self critique assessment: 3
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21:15:50 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> d=rt t=d/r distance divided by rate confidence assessment: 3
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21:15:58 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> self critique assessment: 3
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21:16:21 Given time interval and distance moved how do you get average speed?
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RESPONSE --> d=rt r=d/t Divide distance by time confidence assessment: 3
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21:16:37 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> self critique assessment: 3
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