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course Phy 201
For vs. length for rubber band chain
You suspended 2, 4, 6, 8 and 10 dominoes from a rubber band chain and measured the length of the chain for each number of dominoes.
Insert a copy of your data here, along with any previously submitted work you wish to include:
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Dominoes
At rest the rubber band is 35.55 cm long
2= 1.5 cm (39.7cm)
4 = 3.2cm (41.8cm)
6 = 4.9 cm (43.6 cm)
8 = 7 cm (47.5 cm)
10= 9 cm (51.4 cm)
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Graph the length of the rubber band chain vs. the thickness of your domino stack. If you didn’t actually measure the thickness of each stack you may assume that each is .9 cm thick.
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Graphed the l vs rubber band chain with the thickness on the x axis and the length of the rubber band on the y axis
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Fit a good straight line to you graph. What is the slope of this line?
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Straight line was put on and took two random points on the graph and came up with (40,5, 2.7) and (45, 7). Rise/RUn = 5/4.3 = 1.2
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Describe how you think the actual trend of your data points might differ from linear.
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The more dominoes you put on the rubber band, the more tension is going to be put on it, which will eventually throw off the linearity of the graph because the rubber band will stretch further the more you use it.
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If you fit a good straight line to your first three data points, what is its slope?
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I did the same thing as I did for above but this time I used two points in between the first three points. I used (40.5, 2.7) and (42.7, 4.5) 2.2/1.8= 1.2
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If you fit a good straight line to your last three data points, what is its slope?
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The same
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Assume that a domino stack has a mass density of 20 grams / centimeter of thickness. Relabel your graph so that it measures force vs. length, and give the slope of the graph in terms of force rather than stack thickness.
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??? How do I find the force? I understand that the density for each domino is going to be 180 grams but that does not help me find the force since f= ma
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For example, your first stack is 1.5 cm high. At 20 g / cm that would imply a mass of 30 grams.
The rubber bands were supporting the freely hanging dominoes. Had the rubber bands not been there the dominoes would have accelerated downward at 9.8 m/s^2 or 980 cm/s^2. So you know the mass of the dominoes and the acceleration due to the gravitational force, and you can thus find the gravitational force.
The rubber band tension required to hold the dominoes in equilibrium is equal and opposite to the gravitational force.
You conclusion would be that the tension for the 2-domino case was either about .29 Newtons or about 29 400 dynes.
I think you'll be able to use this explanation to find the five forces (it should also be useful to you in preparing for the final). If you still have questions, feel free to tell me what you do and don't understand about the information, and I'll try to clarify further.
&#Please see my notes and, unless my notes indicate that revision is optional, submit a copy of this document with revisions and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
Be sure to include the entire document, including my notes.
If my notes indicate that revision is optional, use your own judgement as to whether a revision will benefit you. &#
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