#$&* course MTH 174 4:10 p.m. 7/20/10 nGyޑSassignment #016
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15:57:10 Query problem 10.5.12 (3d edition 10.5.12) (was 9.5.12) period 1 fn defined by f(x) = x if 0 < x < 1
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RESPONSE --> Here we have to shift the interval, first by using 2pix and then to move from (-1/2,1/2) to (0,1) interval we use (x - 1/2). So we have 2pi(x-1/2). When we plug this into our formula we get: cos (2pi k (x-1/2)) and sin (2pi k (x-1/2). An equivalent, and simpler, expression is cos (2pi k x) and sin (2 pi k x). It is easy to see that a_o= 1/2. Then it is beneficial to find a general form of the cos and sin integrals using k over our interval. The integral is evaluated using integration by parts and then using the values of our interval we arrive at the general form of: -1/(pi*k) for the b_k and 0 for all a_k. Using this we get: b_1= -1/pi, b_2= -1/2pi b_3= -1/3pi and b_4= -1/4pi.
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15:58:55 what is the fourth degree Fourier polynomial?
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RESPONSE --> After all of the above we put our values into the Fourier equation and we have: f(x) = 1/2 - 1/pi sin(2pi x) - 1/2pi sin (4pi x) - 1/3pi sin(6pi x) - 1/4pi sin (8pi x).
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16:03:03 Describe the graph of this polynomial on [0,1).
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RESPONSE --> The graph is a periodic function and on our interval it is increasing linearly. It's y-intercept is 1/2 and then has a local min about x=0.0968 of 0.0143 and a local max at about x=0.904 of 0.985. The function is also periodic along the line of f(x)=x like a sin wave with its closest values near the middle of the interval and farthest away at the ends.
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16:03:51 What substitution did you use to compensate for the fact that the period of the function is not 2 `pi?
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RESPONSE --> First 2 pi x and then 2pi(x-1/2) to accommodate the [0,1) aspect of the interval.
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16:05:48 Query problem 10.5.24 (3d edition 10.5.24) (was 9.5.24) integral of cos^2(mx) from -`pi to `pi is `pi
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RESPONSE --> Here I used IV- 18 from the table. The integral is thus: 1/2 cos (mx) sin (mx) + x/2. Evaluating this over the interval gives: (0 + pi/2) - ( 0 - pi/2) = pi.
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16:06:07 which formula from the table did you used to establish your result and what substitution did you use?
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RESPONSE --> The formula was IV-18 with n= 2.
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16:09:04 Query Add comments on any surprises or insights you experienced as a result of this assignment.
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RESPONSE --> The first question was pretty difficult for me and took a little while to figure it all out. I also learned Fourier series are important in thermodynamics.
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