Your 'cq_1_01.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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If a ball rolling along a track changes from 10 cm to 20 cm this would mean it is moving over a total of 10 cm. The time difference is 5 seconds between 4s and 9s Assuming this that would mean Change of A equals 10 cm and Change of B= 5s. average rate= 10cm/5s= 2cm/s
10 cm and 20 cm are positions, so quantity A is position and quantity B is change in clock time.
The average rate of change of position with respect to clock time is therefore
ave rate = change in position / change in clock time = 10 cm / (5 s) = 2 cm/s.
The average rate of change of position with respect to clock time is by definition the average velocity.
Your solution was good, except that you did not identify your result as the average rate of change of position with respect to clock time, or velocity.
If a ball rolling along a track changes from 10 cm/s to 40 cm/s this would make a travel time of 30 cm/s. Assuming there is a 3 s time change. 30cm/s / 3s= 10 cm Dr. Smith i do not think i am correct please explain.
Travel time would not be measured in cm / sec. Time is measured in seconds, as are time intervals. 10 cm/s and 40 cm/s are velocities, and 30 cm/s is the change in velocity.
The change in clock time is 3 sec, so the average rate of change of velocity with respect to clock time is
ave rate = change in velocity / change in clock time = 30 cm/s / (3 s) = 30 cm/s / s = 30 cm/s * 1/s = 30 cm/s^2.
If the clock time is 5 cm/second and if the clock time changes by 10 seconds the postion will change 5cm/s x 10s = 50cm
The clock can't read 5 cm/s. Clocks read in units of time, in this case in seconds, not in cm/s.
If your statement is changed to
If the average velocity is 5 cm/second and if the clock time changes by 10 seconds the postion will change 5cm/s x 10s = 50cm
it would be a correct statement, though it doesn't apply to this problem. Here the average velocity is 25 cm/s and the change in clock time is 3 seconds.
You're making a pretty good attempt to follow the definitions. The main difficulty I see is in identifying the information you are given. See my notes and let me know if you have additional questions.