course PHY201
If the velocity of the object changes from 4 cm / sec to 16 cm / sec in 8 seconds, then at what average rate is the velocity changing? ?v/?t=(16cm/s-4cm/s)/(8s-0s)=12/8=1.5cm/s/sA ball rolling from rest down a constant incline requires 8.2 seconds to roll the 97 centimeter length of the incline.
?What is its average velocity?
The formula used is Vavg=(total distance traveled)/(total time) this gives 97cm/8.2s=11.829cm/s
An object which accelerates uniformly from rest will attain a final velocity which is double its average velocity.
?What therefore is the final velocity of this ball? 11.829*2=23.659cm/s
?What average rate is the velocity of the ball therefore changing?
Based on this information to find acceleration you will use (23.659cm/s-0cm/s)/(8.2s-0s)=2.885cm/s/s
An automobile accelerates uniformly down a constant incline, starting from rest. It requires 10 seconds to cover a distance of 132 meters. At what average rate is the velocity of the automobile therefore changing? I must first find the Vave=132m/10s=13.2m/s. I now take vave and times it by 2 to find out the Vf=26.4 m/s. With these I know can find the acceleration which is the change of v/change of t. this will give you 2.64m/s/s
Well done.